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cricket20 [7]
3 years ago
11

the vertex angle of on isosceles triangle measures 42 a base angle in the triangle has a measure given by 2x+3

Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:


Step-by-step explanation:

I take it that the question is What is the value of x.

... Every triangle has a measure of 180o so that is what is on the right side of the equation.

... the Vertex of an isosceles triangle has a unique value. There is only one angle with a measure of 42.

... The Base angles are equal. And there are 2 of them.

Equation

2x + 3 + 2x + 3 + 42 = 180o      

Solution

Combine like terms

2x + 2x + 3 + 3 + 42 = 180  Show the like terms as 1 term for the xs and 1 for the pure numbers on the left.

4x + 48 = 180   Subtract 48 from both sides

4x = 180 - 48    combine

4x = 132            Divide by 4

4x/4 = 132/4

x = 33

Answer

x = 33

2x + 3 = 2*33 + 3 = 69

So the three angles are

69 + 69 + 42

Check

69 + 69 + 42

138 + 42

180 as it should.


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To solve this you need to use the formula for Chord-Chord length. You need to know it, it is ab=cd. with this, we can plug numbers in.
a=30
b=x+1
c=2x-6
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So our new equation is:
30(x+1)=21(2x-6)
30x+30=42x-126
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This isn't what the question is askign for though, it wants YZ
Which is A+B or 30+x+1 or 21+13=34. 
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Answer:

150 + 2x

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Step-by-step explanation:

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Answer:

  a)  CD = 9

  b)  AB = 20

Step-by-step explanation:

<h3>a)</h3>

In this geometry, all of the right triangles are similar. This means The ratio of short side to long side is the same for all of the triangles.

You are given the short and long sides of ΔADB, and the long side of ΔCDA. You are asked for the short side of ΔCDA, so you can write the proportion ...

  CD/AD = AD/BD

  CD/12 = 12/16

  CD = 12(12/16)

  CD = 9

__

<h3>b)</h3>

There are a couple of options for finding AD. One you may be familiar with is the Pythagorean theorem.

  AB² = AD² +DB²

  AB² = 12² +16² = 144 +256 = 400 . . . . fill in known values

  AB = √400 = 20 . . . . . take the square root

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Alternatively, you can use the same proportional relationship that is described above. Here, we make use of the ratio of the hypotenuse to the long side.

  AB/BD = CB/AB

  AB² = BD·CB = 16·(16+9) = 16·25 . . . . cross multiply; fill in known values

  AB = √(16·25) = 4·5 . . . . . take the square root

  AB = 20

_____

<em>Additional comment</em>

This geometry, where the altitude of a right triangle is drawn, has some interesting properties. We have hinted at them above.

You can write three sets of proportions for this geometry: the ratios of short side and long side; the ratios of short side and hypotenuse; and the ratios of long side and hypotenuse. When you look at the way the sides touching the longest hypotenuse relate to that hypotenuse, you see three similar relations:

  AC = √(CD·CB)

  AD = √(DC·DB)

  AB = √(BD·BC) . . . . . . . . the relation used in part (b) above

This "square root of a product" is called the <em>geometric mean</em>. In effect, the length of a side touching the longest hypotenuse is the geometric mean of the two segments of that hypotenuse that it touches.

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