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2 years ago

15

The number of pages that Rick can write varies directly with the amount of the time that he spends writing. He can write 5 pages

in 1/4 hour. How many pages can Rick write in 8 hours?

1 answer:

Gnesinka [82]2 years ago

3 0

Step-by-step explanation:

How many pages can Rick write in 8 hours

= 5 pages / 1/4 hour

= 20 pages / hour

= 20 × 8 / 8 hours

= 160 pages / 8 hours

So, Rick can write 160 pages in 8 hours

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What is 48 x 3/8 is equal to

Valentin [98]

Answer:

18

Step-by-step explanation:

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2 years ago

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The lowest number is 11 the range is 13 and the median is 17 what are the 3 numbers

11Alexandr11 [23.1K]

Answer:

11, 17, and 28.

Step-by-step explanation:

$x, y, z\\$

Lowest number is $x$

Median is $y$

Highest number is $z$

$x=11\\y=17\\\\z-x=17\\z-11=17\\z-11+11=17+11\\z=28\\\\x=11\\y=17\\z=28\\\\11, 17, 28$

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3 years ago

At any point in time, there could be bicycles, tricycles, and

Aleksandr-060686 [28]

Answer:

There may be 1 or 3 tricycles in the parking lot.

Step-by-step explanation:

Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:

13 x 4 + 1 x 3 + 1 x 2 = 57

11 x 4 + 1 x 3 + 3 x 2 = 53

10 x 4 + 3 x 3 + 2 x 2 = 53

8 x 4 + 5 x 3 + 2 x 2 = 51

10 x 2 + 1 x 3 + 4 x 4 = 39

9 x 3 + 1 x 2 + 5 x 4 = 49

Therefore, there may be 1 or 3 tricycles in the parking lot.

6 0

2 years ago

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

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3 years ago

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Aloiza [94]

If it’s a slope- intercept form/ y=mx+b then it’s y=1x+0 because each time it goes up one and over one which is 1/1 or 1 whole and the y-intercept is at (3,0) and we use the Y which is 0

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3 years ago