Answer:
<u><em>x = 4</em></u>
<u><em>x = 3</em></u>
<em><u>x = 10</u></em>
<u><em>x = 3</em></u>
<em><u>x = 16</u></em>
<em><u>x = 35</u></em>
Step-by-step explanation:
x · 10 = 5 · 8
10x = 40
10x ÷ 10 = 40 ÷ 10
<u><em>x = 4</em></u>
x · 8 = 12 · 2
8x = 24
8x ÷ 8 = 24 ÷ 8
<u><em>x = 3</em></u>
x · 3 = 15 · 2
3x = 30
3x ÷ 3 = 30 ÷ 3
<em><u>x = 10</u></em>
x · 12 = 6 · 6
12x = 36
12x ÷ 12 = 36 ÷ 12
<u><em>x = 3</em></u>
x · 2 = 8 · 4
2x = 32
2x ÷ 2 = 32 ÷ 2
<em><u>x = 16</u></em>
x · 2 = 10 · 7
2x = 70
2x ÷ 2 = 70 ÷ 2
<em><u>x = 35</u></em>
Answer:
Rewritten: 15m -3 - 5m
Step-by-step explanation:
15m − ( 3 + 5m )
15m -3 - 5m
10m - 3
Answer:
Given that an article suggests
that a Poisson process can be used to represent the occurrence of
structural loads over time. Suppose the mean time between occurrences of
loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a
4-year period? c). How long must a time period be so that the probability of no loads
occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a
4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads
occurring during that period is at most 0.3 is given by: 3.3 years
Step-by-step explanation:
1.) 4(x+3)
Find the GCF, Greatest Common Factor, of 4x and 12.
4x=2*2*x
12=3*2*2
The greatest common factor is 4. Put this outside of the parentheses. (You would multiply the 2*2)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Solution: 4(x+3)
To check, distribute to see if it works.
4x+12
2.) 2(4r+7)
Find the GCF of 8r and 14
8r=2*2*2*r
14= -1*7*2
The greatest common factor is 2. (There is only 1 two, so you would not multiply them.)
Then, put the rest of the factors as a sum. (Only the factors on the same line.)
Multiply the 2*2*r as one addend and the -1*7 as the other.
Solution: 2(4r-7)
To check, distribute to see if it works.
8r-14
Do you get it now?
3.) 5(x+7)
4.) 7(2x+1)
5.) Cannot be factored.
32x-15
Find the GCF of 32x and -15
32x: 2*2*2*2*2*x
-15: -1*5*3
Because there are no similar factors other than 1, it cannot be factored.
6.) 8(4x+3)
7.) 3(2x-3)
8.) 24(1x+2)
9.) 9(-2x+8)
10.) Cannot be factored
11.) 8(1x+3)
12.) 50(1x+5)
Answer:
Option C
Step-by-step explanation:
Option c is right answer
