Please help me it urgent
1 answer:
You might be interested in
1) Find the derivative 
and 
.
2) The equation of the tangent line is
, so at point (2,6): 
and
-the equation of the tangent line at point (2,6).
2) The equation of the tangent line is
The coordinates of point B' are (-3, 6).
<h2>Given that</h2>Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).
The triangle is translated as 3 units to the left and 1 unit up.
<h3>We have to determine</h3>What are the coordinates of B' after the translation?
<h3>According to the question</h3>Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).
The triangle is translated as 3 units to the left and 1 unit up.
To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.
After the given transformation the coordinates of point B' would be:
Therefore, the coordinates of point B' are (-3, 6).
To know more about Transformation click the link given below.