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1 year ago

BD and AC are directors of .0 identify each Arc as a minor Arc interior Arts Elementary art

Mathematics

1 answer:

Maru [420]1 year ago

5 0

Given BD and AC is a diameter of the circle:

We need to find the following:

1. measure of the arc BA

So,

the measure of the minor arc BA = 44

The measure of the major arc BA = 360 - 44 = 316

2. the measure of the arc ACB = 360 - 44 = 316

3. The arc BCD is a semicircle of the circle

So, the measure of the arc BCD = 180

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Using the triangle below, find the value of x.

xenn [34]

Answer:

Step-by-step explanation:

it looks like the right anwser

3 0

3 years ago

Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ

solong [7]

Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.

3 0

3 years ago

The table shows the weights of a sample of packages carried by an air freight company last month. Find the mean deviation for th

podryga [215]

Answer:

1.52

Step-by-step explanation:

$\frac{5 + 9 + 5 + 6 + 8 }{5} = \frac{33}{5} = 6.6$

distance from 6.6

5, 1.6

9, 2.4

5, 1.6

6, .6

8, 1.4

$\frac{1.6 + 2.4 + 1.6 + .6 + 1.4}{5} = \frac{7.6}{5} = 1.52$

3 0

3 years ago

The volume of a soap bubble is 1,203.6 mm^3. Find the radius and diameter of the soap bubble. Use 3.14 for it.

madreJ [45]

The radius of the soap bubble=6.6 mm

The diameter of the soap bubble=13.2 mm

Step-by-step explanation:

The volume of the soap bubble is given in the problem and using this information we have to calculate its radius and diameter.

$volume=1203.6mm^3$

The soap bubble is in the shape of a sphere and we can use the equation of the volume of the sphere in this problem.

$volume=\frac{4}{3} \pi r^3\\1203.6=\frac{4}{3} \times 3.14\times r^3\\r^3=\frac{1203.6\times 3}{4\times3.14} \\r^3=287.48\\r=6.59 mm$

The radius of the soap bubble is 6.6 mm.

$diameter=2\times radius\\=2\times 6.6\\13.2 mm$

The diameter of the soap bubble is 13.2 mm

8 0

3 years ago

Solve the system using elimination. -9x - 4y = 1 3x + 3y = 3 ([?], [])

irakobra [83]

Step-by-step explanation:

-9x-4y=1....eq1

3x+3y=3.....eq2

multiply eq2 by 3

to get

9x+9y=9....eq3

add eq1 and 3

0+5y=10

5y=10

divide both sides by 5

y=2

substitute y=2 in to eq1

-9x-4(2)=1

-9x-8=1

grouping of like terms

-9x=1+8

-9x=9

divide both sides by -9

x= -1

now the answer is

x= -1, y=2

7 0

3 years ago