The probability that the train will be there when Alex arrives is 0.1.
Given that the time that train arrives between 1:00 P.M to 2:00 P.M. and waits for 10 minutes. Alex arrives between 1:00 P.M to 2:00 P.M.
We are required to find the probability that the train when Alex arrives.
Probability is the likeliness of happening an event among all the events that are possible to happen.
Probability=Number of items/total number of items.
Number of combinations of timings in which the train may have arrived=60/10=6 combinations
Number of ways in which Alex arrives at the station=60.
Probability=6/60
=1/10
=0.1
Hence the probability that the train will be there when Alex arrives ie 0.1.
Question is incomplete. The following things should be included:
Timing in which train arrives is between 1:00 P.M and 2:00 P.M.The train waits for 10 minutes. Alex arrives between 1:00 P.M and 2:00 P.M.
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60+60+80=200 there you go I believe
Answer:
Area = x4 + 4x3 + 3x2 - 4x - 4
Length = x3 +5x2 + 8x + 4
Width = Area / Length.
Performing long division with polynomial.
x4 + 4x3 + 3x2 - 4x - 4 / x3 + 5x2 + 8x + 4 = x-1
Width = x-1
Step-by-step explanation:
Answer:
Distance = 73 m
Step-by-step explanation:
Given that,
The length of a rectangle = 48 m
The width of a rectangle = 55 m
We need to find the diagonal distance. We can use the Pythagoras theorem to find it.
So, the required distance is equal to 73 m.
Answer:
∠ PRQ = 55°
Step-by-step explanation:
The angle subtended at the centre by an arc is twice the angle subtended at the circumference by the same arc, thus
∠ PQR = 0.5 × 110° = 55°
