For this case we have that by definition, the volume of a cone is given by:
![V = \frac {1} {3} * \pi * r ^ 2 * h](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%20%7B1%7D%20%7B3%7D%20%2A%20%5Cpi%20%2A%20r%20%5E%202%20%2A%20h)
Where:
r: It is the radius of the cone
h: It is the height of the cone
According to the statement data we have:
![h = 12 \ cm\\V = 125 \ cm ^ 3](https://tex.z-dn.net/?f=h%20%3D%2012%20%5C%20cm%5C%5CV%20%3D%20125%20%5C%20cm%20%5E%203)
Substituting in the formula:
![125 = \frac {1} {3} * \pi * r ^ 2 * 12](https://tex.z-dn.net/?f=125%20%3D%20%5Cfrac%20%7B1%7D%20%7B3%7D%20%2A%20%5Cpi%20%2A%20r%20%5E%202%20%2A%2012)
We cleared the radius:
![3 * 125 = \pi * r ^ 2 * 12\\\frac {3 * 125} {12 \pi} = r ^ 2\\9.9522 = r ^ 2\\r = \pm \sqrt {9.9522}](https://tex.z-dn.net/?f=3%20%2A%20125%20%3D%20%5Cpi%20%2A%20r%20%5E%202%20%2A%2012%5C%5C%5Cfrac%20%7B3%20%2A%20125%7D%20%7B12%20%5Cpi%7D%20%3D%20r%20%5E%202%5C%5C9.9522%20%3D%20r%20%5E%202%5C%5Cr%20%3D%20%5Cpm%20%5Csqrt%20%7B9.9522%7D)
We choose the positive value:
![r = 3.1547](https://tex.z-dn.net/?f=r%20%3D%203.1547)
We round and we have that the radius of the cone is:
![r = 3.16 \ cm](https://tex.z-dn.net/?f=r%20%3D%203.16%20%5C%20cm)
ANswer:
![r = 3.16 \ cm](https://tex.z-dn.net/?f=r%20%3D%203.16%20%5C%20cm)
A.) <span> Number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. A dot is made at 1.7 and labeled as square root of 3. </span>
To get the center of the measurement, you. could use a ruler.
Answer:
They lie in different planes and will never intersect
Step-by-step explanation:
Skew lines are lines that are noncoplanar and do not intersect
Answer: B. Graph of 2 lines that intersect at one point. Both lines are solid. One line passes through (-2,2) and (0,3) and is shaded below the line.
y < = 1/2x + 3...(-2,2) y < = 1/2x + 3....(0,3)
2 < = 1/2(-2) + 3 3 < = 1/2(0) + 3
2 < = -1 + 3 3 < = 0 + 3
2 < = 2 (correct) 3 < = 3 (correct)
The other line passes through points (0,1) and (1,-2) and is shaded above the line.
y > = -3x + 1...(0,1) y > = -3x + 1...(1,-2)
1 > = -3(0) + 1 -2 > = -3(1) + 1
1 > = 0 + 1 -2 > = -3 + 1
1 > = 1 (correct) -2 > = -2 (correct)