Step-by-step explanation:
1. f(x) = 12x + 1
f(-2) = 12(-2) + 1 = -23
f(0) = 12(0) + 1 = 1
f(3) = 12(3) + 1 = 37
2. p(x) = -8x - 2
p(-2) = -8(-2) - 2 = 14
p(0) = -8(0) - 2 = -2
p(3) = -8(3) - 2 = -26
3. m(x) = -6.5x
m(-2) = -6.5(-2) = 13
m(0) = -6.5(0) = 0
m(3) = -6.5(3) = -19.5
4. s(x) = ⅖x + 3
s(-2) = ⅖(-2) + 3 = -⅘ + 3 = 11/5
s(0) = ⅖(0) + 3 = 3
s(3) = ⅖(3) + 3 = 6/5 + 3 = 21/5
5. h(x) = ¾x - 6
h(-2) = ¾(-2) - 6 = -6/4 - 6 = -30/4
h(0) = ¾(0) - 6 = -6
h(3) = ¾(3) - 6 = 9/4 - 6 = -15/4
I would say that it it "12y represents the value of the truffles." Imean it literally says it in the question but here you go.
Answer:
B.
Step-by-step explanation:
BECAUSE IT IS
Step-by-step explanation:
15) 50 ÷ 2 = 25
17) Mean = 301, Mode = 40-50
(10+20) ÷ 2 = 15, (20+30) ÷ 2 = 25, (30+40) ÷ 2 = 35
(40+50) ÷ 2 = 45, (50+60) ÷ 2 = 55, (60+70) ÷ 2 = 65
(70+80) ÷ 2 = 75
• 15×4 = 60, 25×8 = 200, 35×10 = 350, 45×12 = 540
55×10 = 550, 65×4 = 260, 75×2 = 150
Mean = (60+200+350+540+550+260+150) ÷ 7
= 2110 ÷ 7
= 301.4285....
= 301
Mode : the highest frequency
Answer:
Step-by-step explanation:
The formula you will want to use for this is one that allows a certain number of compoundings of the interest per year. This is a specific one for compounding continuously, and there is one for finding simple interest. Here is the one we want:
where A(t) is the amount in the account after the compounding occurs over the number of years specified, P is the initial amount in the account, r is the interest rate in decimal form, n is the number of times per year the compounding occurs, and t is the amount of time the money is in the account in years. For us:
P = 300,
r = .04,
n = 4 (quarterly means 4 times), and
t = 10
Filling in:
and
and
and
A(t) = 300(1.488863734) so
A(t) = $446.66 or $447
