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inna [77]
3 years ago
11

If i have 2 apples and eat one and give the other away how many are their.

Mathematics
1 answer:
Sphinxa [80]3 years ago
5 0
There will be 0 apples left since you have one away and ate the other
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Below are the steps to solve an equation:
otez555 [7]

Answer:

x-5=-3

Step-by-step explanation:

|x-5|+2=5

|x-5|=5-2

|x-5|=3

x-5=±3

so x-5=-3 is a correct step.

4 0
3 years ago
Suppose that x has a binomial distribution with n = 201 and p = 0.45. (Round np and n(1-p) answers to 2 decimal places. Round yo
ycow [4]

Answer:

a) It can be used because np and n(1-p) are both greater than 5.

Step-by-step explanation:

Binomial distribution and approximation to the normal:

The binomial distribution has two parameters:

n, which is the number of trials.

p, which is the probability of a success on a single trial.

If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.

In this question:

n = 201, p = 0.45

So, lets verify the conditions:

np = 201*0.45 = 90.45 > 5

n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5

Since both np and n(1-p) are greater than 5, the approximation can be used.

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3 years ago
Help please !! It’s geometry credit recovery
mr Goodwill [35]
Cross multiply? 9x2=18/3= 6

5 0
3 years ago
Which statement about solving inequalities is true?
PIT_PIT [208]

None of the statements on that list is true.

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3 years ago
Read 2 more answers
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successi
My name is Ann [436]

Answer:

option C

c. least: $101

greatest: $1001

Step-by-step explanation:

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.

Sum of 10 prizes = 5510

100 is the difference. there is a common difference d=100

So its a arithmetic sequence

the sum formula for arithmetic sequence is

S_n = \frac{n}{2}(2a_1 +(n-1)d)

Sn = 5510, n=10 n d= 100 we need to find out first term a1

5510 = \frac{10}{2}(2a_1 +(10-1)100)

5510 = 5 (2a1 + 900)

5510 = 10a1 + 4500

Subtract 4500 on both sides

1010= 10a1

divide by 10 on both sides

a1 = 101

so first term that is least term is 101

To find out greatest term we use formula

a_n = a_1 + (n-1) d

a(10) = 101 + (10-1)100

= 101 + 900= 1001

greatest is 1001

4 0
3 years ago
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