The equation of the line in the point-slope form is y - 15 =
(x - 10)
Step-by-step explanation:
The point-slope form of a linear equation is
, where
- m is the slope of the line, where
,
and
are two points on the line
is a point on the line
∵ Point A = (10 , 15)
∵ The x-coordinate of the second point is 125% of x-coordinate
of point A
∴ x-coordinate of second point =
× 10
∴ x-coordinate of second point = 12.5
∵ The y-coordinate of the second point is 75% of y-coordinate
of point A
∴ y-coordinate of second point =
× 15
∴ y-coordinate of second point = 11.25
∴ The coordinates of the second point are (12.5 , 11.25)
Let us find the slope of the line by using the rule of it above
∵
= (10 , 15)
∵
= (12.5 , 11.25)
∴ 
Now we can write the equation
∵ The point-slope form is 
∵ 
∵
= (10 , 15)
- Substitute these values in the form of the equation
∴ y - 15 =
(x - 10)
The equation of the line in the point-slope form is y - 15 =
(x - 10)
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Answer:
y=-3x+5
Step-by-step explanation:
it parallel to 3x+y+2=0 => line is: 3x+y+c=0
It through (3;-4) => 3(3)+(-4)+c=0 <=> c=-5
Line is 3x+y-5=0 => y=-3x+5
Step-by-step explanation:

The missing expression should be for Step 3 is [(25 + 3)/0.5] - 16.4 ÷ 4 and the missing expression should be for Step 6 is 56 - 4.1
<h3>Part A: Explain what the missing expression should be for Step 3</h3>
To do this, we make use of the expression in step 2
The expression in step 2 is
[(5^2 + 3)/0.5] - 16.4 ÷ 4
The next step at this stage is to evaluate the expression 5^2
So, we have:
[(25 + 3)/0.5] - 16.4 ÷ 4
Hence, the missing expression should be for Step 3 is [(25 + 3)/0.5] - 16.4 ÷ 4
<h3>Part B: Explain what the missing expression should be for Step 6.</h3>
To do this, we make use of the expression in step 5
The expression in step 5 is
56 - 16.4 ÷ 4
The next step at this stage is to evaluate the expression 16.4 ÷ 4
So, we have:
56 - 4.1
Hence, the missing expression should be for Step 6 is 56 - 4.1
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Answer:
for 1 pound =10/22
for 51/ 2 pounds = 10/22x51/2
= 510/ 44
= 11.590kg
Step-by-step explanation: