Answer:
Y = 2
Step-by-step explanation:
Solve for Y:
(3 + 5)×2 Y = 5×8 - 2×4
3 + 5 = 8:
8×2 Y = 5×8 - 2×4
5×8 = 40:
8×2 Y = 40 - 2×4
-2×4 = -8:
8×2 Y = -8 + 40
8×2 = 16:
16 Y = 40 - 8
40 - 8 = 32:
16 Y = 32
Divide both sides of 16 Y = 32 by 16:
(16 Y)/16 = 32/16
16/16 = 1:
Y = 32/16
The gcd of 32 and 16 is 16, so 32/16 = (16×2)/(16×1) = 16/16×2 = 2:
Answer: Y = 2
Answer:
w = 12.38
Step-by-step explanation:
w - 2.58 = 9.8
add 2.58 to both sides
w = 12.38
Step-by-step explanation:
it will be a because it have more
Answer:
-2 < -1
Step-by-step explanation:
-6 < -3
-6/3 < -3/3
-2 < -1
The practical domain of time is t ∈ [0, 4.25s].
- The set of values that make feel in a particular context is referred to as the sensible area.
- All feasible solutions are addressed by way of theoretical domains and stages.
- domain names and stages restrict the solution sets such that they may be realistic in the parameters given
- .The ball begins its motion at time t = 0s.
- To locate the time while the ball hits the floor,
- we solve the equation:
- h(t) = -16t² + 68t
- h(t) = 0
- -16t² + 68t = 0
- t(-16t + 68) = 0
- t = 0 and -16t + 68 = 0.
- 16t = 68
- t = 68/16
- t = 4.25
- h(t) is non-negative within the interval [0, 4.25].
- Hence, the practical domain is 0 ≤ t ≤ 4.25 s.
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