Consider the power 34.

A right angled triangle has two side lengths of 14cm and 7cm. Work out the length of x

kati45 [8]

Answer:

15.65

Step-by-step explanation:

a^2+b^2=c^2

7^2+14^2=c^2

add 49+196=245

245=c^2

square root everything to get 15.65

6 0

4 years ago

Which is the best approximation for the measure of angle ABC?

ankoles [38]

We can find the approximate measurement of angle ABC and it is equal to 180°. The summation of all angles in a triangle is 180°.
Solving for x or angle B, we need to used Pythagorean theorem and SOH CAH TOA.
Solving for angle A:
sinA = 10.5/20
A = 31.67°

Solving for angle B:
180° = ∠C + ∠B + ∠A
180° = 90° + ∠B + 31.67
∠B = 58.33°

The x value is 58.33°.

3 0

3 years ago

Question 1: Whose percentage increased more from 1984 to 2014, males or females? By how much more did it increase?

garik1379 [7]

The percentage increase are applied to the number of male and female

from the previous period.

From 1984 to 2014, the percentage of females increased more than males.

Reasons:

Let F represent the initial number of females and let M represent the initial number of males before 1984.

We have;

In 1984

Number of females = F × 1.026 = 1.026·F

number of males = M × 1.031 = 1.031·M

In 1994

Number of females = 1.026·F × 1.032 = 1.058832·F

Number of males = 1.031·M × 1.032 = 1.063992·M

In 2004

Number of females = 1.058832·F × 1.056 = 1.118126592·F

Number of males = 1.063992·M × 1.049 = 1.116127608·M

In 2014

Number of females = 1.118126592·F × 1.066 = 1.191922947072·F

Number of males = 1.116127608·M × 1.059 = 1.181979136872·M

Therefore, between 1984 and 2014, we have;

The percentage increase of females = 1.191922947072 × 100 - 100 ≈ 19.2%

The percentage increase of males = 1.181979136872 × 100 - 100 ≈ 18.2%

Therefore;

The percentage increase of the females is more than the males by (1.191922947072 × 100 - 100) - (1.181979136872 × 100 - 100) ≈ 0.994%

Learn more about percentages and compounded percentages here:

brainly.com/question/3783619

brainly.com/question/1301322

8 0

3 years ago

How do I construct bisectors, angles, & segments?

Doss [256]

Answer:

Step-by-step explanation:

These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.

1. Angle construction:

Given an angle. construct an angle congruent to the given angle.

Given: Angle ABC

Construct: An angle congruent to angle ABC

Procedure:

1. Draw a ray. Label it ray RY.

2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.

3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.

4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.

5. Draw ray RQ.

Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.

You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.

4 0

3 years ago

which of the following numbers has the least number of positive divisors if a=50^(100) . choose: 1)25a 2)4a 3)3a 4)26a 5)10a

Nuetrik [128]

Answer:

the answer would have to be B

Step-by-step explanation:

3 0

3 years ago