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3 years ago

7

Write the x-intercept of the graph of 2x − y = 5.

1 answer:

aleksley [76]3 years ago

5 0

The answer is X=5/2+y/2

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Mrs Brown and Mrs Jones make 4 dozen sandwiches in half an hour in Mrs Jones’ small kitchen. If they had 30 friends in to help,

Pepsi [2]

Answer:

1488 sandwiches in thirty minutes

Step-by-step explanation:

5 0

3 years ago

Pls help I literally have no clue what this means

Elina [12.6K]

Answer:

I think the answer is c -2

Step-by-step explanation:

but don't quote me on that and if it's wrong i truly am sorry

8 0

2 years ago

Read 2 more answers

The mean of a population is 74 and the standard deviation is 16. The shape of the population is unknown. Determine the probabili

bulgar [2K]

Answer:

a

$P(X > 75)= 0.35402$

b

$P(72 < X < 75 ) = 0.2529$

c

$P( X < 74.7) = 0.74041$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 74$

The population standard deviation is $\sigma = 16$

Considering question a

The sample size is n = 36

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{16}{\sqrt{36} }$

=> $\sigma_{x} = 2.67$

Generally the probability that a random sample of size 36 yielding a sample mean of 75 or more is mathematically represented as

$P(X > 75) = P( \frac{X - \mu }{ \sigma_{x}} > \frac{75 - 74}{ 2.67 } )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

$P(X > 75) = P(Z > 0.3745 )$

From the z table the area under the normal curve representing 0.3745 to the right is

$P(Z > 0.3745 ) = 0.35402$

=> $P(X > 75)= 0.35402$

Considering question b

The sample size is n = 104

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{16}{\sqrt{104} }$

=> $\sigma_{x} = 1.5689$

Generally the probability that a random sample of size 104 yielding a sample mean between 72 and 75 is mathematically represented as

$P(72 < X < 75 ) = P(\frac{72 - 74 }{1.5689} < \frac{X - \mu }{\sigma_{x}} < \frac{75 - 74 }{1.5689} )$

=> $P(72 < X < 75 ) = P(-1.275 < Z < 0.375 )$

=> $P(72 < X < 75 ) = P(Z < 0.375 ) - P(Z < -1.275)$

From the z table the area under the normal curve representing -1.275 to to the left is

$P(Z < -1.275) =0.10115$

=> $P(72 < X < 75 ) = 0.35402 - 0.10115$

=> $P(72 < X < 75 ) = 0.2529$

Considering question c

The sample size is n = 217

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{16}{\sqrt{217} }$

=> $\sigma_{x} = 1.086$

Generally the probability that a random sample of size 217 yielding a sample mean of less than 74.7 is mathematically represented as

$P( X < 74.7) = P(\frac{X - \mu }{\sigma_x} < \frac{ 74.7 - 74 }{ 1.086 })$

=> $P( X < 74.7) = P(Z < 0.6446 )$

From the z table the area under the normal curve representing 0.6446 to to the left is

$P(Z < 0.6446 ) = 0.74041$

=> $P( X < 74.7) = 0.74041$

8 0

3 years ago

Challenger Elementary School has 800800800 students. Every Wednesday, 12\%12%12, percent of the students stay after school for C

Hunter-Best [27]

Ummm if the numbers are 800 and 12% the answer is 96 students
12/100=x/800
100x=9600
x=96

7 0

4 years ago

In exercises 18 and 19 determine which solution if any is an extraneous solution 18.sprt(3x-2)=x; x=1,x=2. 19. Sprt(x+6=x; x=3,x

agasfer [191]

ANSWER

18. No extraneous solution.

19. The extraneous solution is x=-2

EXPLANATION

18. The given radical equation is:

$\sqrt{3x - 2} = x$

Solving this radical equation yields

$x=1,x=2$

We check for an extraneous solution by substituting each value into the equation.

Checking for x=1,

$\sqrt{3 \times 1 - 2} = 1$

$\sqrt{3- 2} = 1$

$\sqrt{1} = 1$

$1 = 1$

This is true.

Checking for x=2

$\sqrt{3 \times 2- 2} = 2$

$\sqrt{6- 2} = 2$

$\sqrt{4} = 2$

$2 = 2$

This is also true. Hence there is no extraneous solution.

19. The given radical equation is:

$\sqrt{x + 6} = x$

Solving this equation yields,

$x=3,x=-2$

Checking for x=3,.

$\sqrt{3+ 6} = 3$

$\sqrt{9} = 3$

3=3.

This is a true solution.

Checking for x=-2.

$\sqrt{ - 2 + 6} = - 2$

$\sqrt{4} = - 2$

$2 \ne - 2$

Hence x=-2 is an extraneous solution.

5 0

4 years ago