This shows that Marco can buy at most 5 pencils
<h3>Inequalities</h3>
- Let the price of each pencil Marco can buy be "x"
If the cost of markers is $4, and the cost of each lead pencil is $3 with at most $15 spent, hence;
Subtract 4 from both sides
3x ≤ 15
x ≤ 15/3
x ≤ 5
This shows that Marco can buy at most 5 pencils
Learn more on inequalities here:
brainly.com/question/24372553
To find what the value of the digit 8 is, we can start by moving from the right. In a number, the place value goes (from right to left) ones, tens, hundreds, thousands, ten-thousands, hundred-thousands, millions and so on. Now we can find out what each of the numbers is.
Since 3 is the first, that means 3 is in the ones place.
Since 9 is second, that means that 9 is in the tens place.
Since 2 is third, that means that 2 is in the hundreds place.
Since 6 is fourth, that means that 6 is in the thousands place.
Now, we have 8. Since 8 is fifth, that means that 8 is in the ten-thousands place. But that's not the value of the eight. The value of the 8 would be it's place value (10,000) times 8. 10,000 * 8 = 80,000, so the value of the digit 8 in the number 686293 is 80,000.
Answer:
Step-by-step explanation:
if the number of votes is 25, 12 is not majority
but if the number is 23 then 12 is majority
The estimate of the sum of 202 and 57 is 260. You add the numbers together and than round up.
Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.
<h3>What is the binomial distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 0.54% of the calls receive a busy signal, hence p = 0.0054.
- A sample of 1300 callers is taken, hence n = 1300.
The probability that at least 5 received a busy signal is given by:
In which:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).
Then:
Then:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.
0.8295 = 82.95% probability that at least 5 received a busy signal.
More can be learned about the binomial distribution at brainly.com/question/24863377
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