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scoray [572]
3 years ago
7

What two numbers have a product of -15 and a sum of -2?​

Mathematics
2 answers:
lesantik [10]3 years ago
5 0

Answer:

-5 and 3

Step-by-step explanation:

(-5)(3)= -15

and

-5+3= -2

Kruka [31]3 years ago
4 0

Answer:

-5 and 3.

Step-by-step explanation:

-5x3=-15 -5-3=-2

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Okay so I'm working on this assignment and I see this question and I'm very confused, aren't the first 2 answers the same and th
Serjik [45]

Answer:

actually no.

Step-by-step explanation:

I assume you know the 4 inequalites:

The 4 Inequalities

Symbol      Words               Example

>          greater than        x+3 > 2

<             less than         7x < 28

≥ greater than or equal to 5 ≥ x−1

≤    less than or equal to 2y+1 ≤ 7

The "open circle" represents less than or greater than, and the "closed circle" represents greater than or equal to or less than or equal to.

<em><u>Hope it helps! Have a great day! :) let me know if it helped</u></em>

5 0
3 years ago
Read 2 more answers
How many gallons are in 50 liters? rounded answer to the neareast tenth
mestny [16]

Answer:

It would be 13 but since to the nearest tenth it would be 10

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How would you find an interquartile range with just numbers?
Stolb23 [73]

Answer:

IQR is 3.5

Step-by-step explanation:

<u>Step 1: Organize the numbers in numerical order</u>

0,0,2,2,3,4,6,8

<u>Step 2: Break the set up into quartiles (4 parts)</u>

0 0 | 2 2 | 3 4 | 6 8

<u>Step 3: Find the average of each quartile</u>

0 | 2 | 3.5 | 7

<u>Step 4: Find the IQR (Q3-Q1)</u>

3.5-0=3.5

Therefore, the IQR is 3.5

8 0
3 years ago
Use the given data to find the minimum sample size required to estimate the population proportion. margin of​ error: 0.0080.008​
nadezda [96]

Formula for the Minimum Sample size n=(\frac{z}{E})^2\hat{p}\hat{q}

The least biased estimate for p and q is 1/2.

z_{\frac{\alpha }{2}}=z_{{0.01}{2}}=2.58

Thus

n=(\frac{2.58}{0.08})^2*0.5*0.5

n=260.015

n\approx260

3 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
3 years ago
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