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saw5 [17]
3 years ago
14

What are the domain and range

Mathematics
2 answers:
nydimaria [60]3 years ago
4 0
The domain is the x-values and the range is the y-values of an ordered pair
natta225 [31]3 years ago
3 0

For this case, the first thing we must do is observe that the graph has two asymptotes.

A horizontal asymptote or equivalently:

y = 0

A vertical asymptote or equivalently:

x = 0

Therefore, the domain and the range of the function is the same:

All reals excluding zero.

Answer:

The domain and range is the mime:

All reals excluding zero.

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\frac{1}{2} \int\limits^{\frac{\pi}{5}} _0 {(3\ sin(5\theta))^2} \, d\theta\\\\&#10;=\frac{9}{4} \int\limits^{\frac{\pi}{5}} _0 {(1-cos(10\theta))} \, d\theta\\\\&#10;=\frac{9}{4} [\theta-\frac{sin(10\theta)}{10}]^\frac{\pi}{5}} _0 \\\\&#10;=\frac{9\pi}{20}

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3 years ago
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The answer is number option 4

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What is the equation of the line that passes through (-5, 0) and (4, 3)?
kotegsom [21]

Answer:

y = 1/3x + 5/3

Step-by-step explanation:

An equation contains a slope and y-intercept, in the form y = mx + b. To find the slope or m, you need to plug the coordinates into the slope formula.

y2 - y1/ x2 - 1

3 - 0/ 4 - (-5)

= 3 / 9

= 1/3

Now that we know the slope, we need to plug the values of x and y to find the y-intercept.

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3 0
3 years ago
HELP WITH MATH PLEASE
maksim [4K]

Answer:

  • 0.25|h -1600| -400
  • 1000
  • 2200

Step-by-step explanation:

Once again, you can choose the correct equation by finding the one that gives d=0 for h=0. (Note that the problem statement requires the independent variable to be h, not x.)

Then you can use that equation to find h for d=-250:

  -250 = 0.25|h -1600| -400

  150 = 0.25|h -1600|

  600 = |h -1600|

This resolves to two equations:

  • -600 = h -1600 . . . ⇒ . . . h = 1000
  • 600 = h -1600 . . . ⇒ . . . h = 2200

__

Or, you can realize the distance from the west end is 4 times the depth. At a depth of 250 ft, that distance is h=1000 ft. That is 600 ft from the center, so 1200 ft from the same depth on the other side of the crater, which is at h=2200 ft.

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