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Lynna [10]
3 years ago
14

13 and 15 is something I need help on it would nice if you added work so I could answer the steps thank you

Mathematics
1 answer:
netineya [11]3 years ago
8 0

check the attachment for answer no. 13

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
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Answer:

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Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

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Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

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x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

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In this question:

y = -16x^2 + 177x + 98

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So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

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x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

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