Using the data for each truck lets calculate,
median for truck 1 - 511.5
median for truck 2 - 650.5
lets consider each statement
A.medians for both trucks are the same - wrong
median for 1 and 2 are 511.5 and 650.5 respectively
B. the two trucks sold most number of tacos on 3rd day
truck 1 sold 437 on day 3 but highest number it sold was 721 on day 1
truck 2 sold 426 on day 3 but highest number was 732 on day 6
therefore this statement too is wrong
C.
truck 1 - range between maximum(721) and minimum(425) = 296
truck 2 - maximum (732) and minimum (426) difference = 306
the range between maximum and minimum in truck 2 is 306 thats greater than range between maximum and minimum in truck 1, that's 296
therefore this statement is correct
D.
total number of tacos for each truck -
truck 1 - 5291
truck 2 - 6107
food truck 1 sold less than truck 2 therefore this statement too is wrong
Answer: Quadratic
Solution
X=0
X=- 1/3
Hello!
You have to find the probability of getting a 2
This is a 1/6 chance
Then you have to find the chance of getting a number greater than 2
This is a 4/6 chance
To find the chance of these happening at the same time you multiply these together
1/6 * 4/6 = 1/9
There is a 1/9 chance
Hope this helps!
