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xxTIMURxx [149]
3 years ago
12

Lorinda has 101010 books on her bookshelf. \blue{\text{$6$}}6start color #6495ed, start text, 6, end text, end color #6495ed of

these books have \blue{\text{blue covers}}blue coversstart color #6495ed, start text, b, l, u, e, space, c, o, v, e, r, s, end text, end color #6495ed, and \red{\text{$4$}}4start color #df0030, start text, 4, end text, end color #df0030 have \red{\text{red covers}}red coversstart color #df0030, start text, r, e, d, space, c, o, v, e, r, s, end text, end color #df0030. \blue{\text{$3$}}3start color #6495ed, start text, 3, end text, end color #6495ed of the blue books are \blue{\text{mystery novels}}mystery novelsstart color #6495ed, start text, m, y, s, t, e, r, y, space, n, o, v, e, l, s, end text, end color #6495ed, and \blue{\text{$3$}}3start color #6495ed, start text, 3, end text, end color #6495ed are \blue{\text{fantasy novels}}fantasy novelsstart color #6495ed, start text, f, a, n, t, a, s, y, space, n, o, v, e, l, s, end text, end color #6495ed. \red{\text{$2$}}2start color #df0030, start text, 2, end text, end color #df0030 of the red books are \red{\text{mystery novels}}mystery novelsstart color #df0030, start text, m, y, s, t, e, r, y, space, n, o, v, e, l, s, end text, end color #df0030, and \red{\text{$2$}}2start color #df0030, start text, 2, end text, end color #df0030 are \red{\text{fantasy novels}}fantasy novelsstart color #df0030, start text, f, a, n, t, a, s, y, space, n, o, v, e, l, s, end text, end color #df0030. Lorinda closes her eyes and randomly selects a book from her bookshelf. Let AAA be the event that she selects a blue book and BBB be the event that the book is a fantasy novel. Which of the following statements are true? Choose all answers that apply: Choose all answers that apply: (Choice A) A P(A\text{ | }B)=P(A)P(A | B)=P(A)P, left parenthesis, A, start text, space, vertical bar, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, the conditional probability that Lorinda selects a blue book given that she has chosen a fantasy novel is equal to the probability that Lorinda selects a blue book. (Choice B) B P(B\text{ | }A)=P(B)P(B | A)=P(B)P, left parenthesis, B, start text, space, vertical bar, space, end text, A, right parenthesis, equals, P, left parenthesis, B, right parenthesis, the conditional probability that Lorinda selects a fantasy novel given that she has chosen a blue book is equal to the probability that Lorinda selects a fantasy novel. (Choice C) C Events AAA and BBB are independent events. (Choice D) D The outcomes of events AAA and BBB are dependent on each other. (Choice E) E P(A\text{ and }B)=P(A) \cdot P(B)P(A and B)=P(A)⋅P(B)P, left parenthesis, A, start text, space, a, n, d, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, dot, P, left parenthesis, B, right parenthesis, the probability that Lorinda selects a book that is blue and a fantasy novel is equal to the probability that Lorinda selects a blue book multiplied by the probability that she selects a fantasy novel.
Mathematics
1 answer:
expeople1 [14]3 years ago
7 0
Omg Bruh what is this Lol
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Rsm question please explain<br> The question is in the picture
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A triangle is a three-edged polygon with three vertices. ΔAKE and ΔCKP are congruent.

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angle of a triangle is always equal to 180°.

In ΔABC, since AB≅BC, therefore, the triangle will be an isosceles triangle, and the measure of ∠A ≅ ∠C, using the base angle theorem.

Now In ΔAKE and ΔCKP,

∠A ≅ ∠C {Proved above}

∠AKE ≅ ∠CKP {Given}

AK ≅ KC {Given }

Since two angles and a side of the triangle are equal, therefore, we can write the two triangle are congruent using the Side-angle-side or Angle-Side-Angle congruence.

Hence, ΔAKE and ΔCKP are congruent.

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brainly.com/question/2773823

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the original price of a DVD is $11. The sale price is 30% off the original price. what is the sale price of the DVD?
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A bag contains 40 marbles. The probability of selecting a red marble at random is 1/5. How many red marbles are in the bag?
goblinko [34]

Answer:

8 red marbles.

Step-by-step explanation:

All together we have 40 marbles. The fraction of marbles that are red is 1/5 which means that we should divide the total number of marbles, which is 40 by the denominator ( Bottom number of fraction ) 5 so that we get the number of groups that have 1 red marble in them. In this case we have 8 groups.

40/5=8

You always divide by the denominator ( Bottom number of fraction ) first and then you multiply your answer by the numerator ( Top number of fraction ) .

If each group has 1 red marble in it and we have 8 groups, it means that we have 8 red marbles in the bag.

1 * 8 = 8 red marbles in the bag

If the numerator (number above the fraction line) was more than one, then this would mean that we have more than 1 marble in each group of marbles.

Example:

If we had 3/5 we would have 3 marbles in each group of marbles. This means that instead of doing 1 * 8 we would have to do 3 * 8 = 24. We would have 24 red marbles in the bag.

Easy and quick way if you do not need the explanation:

Another way we could do this is by simply multiplying the fraction ( 1/5 ) by the total number of marbles ( 40 ). This would still give us an answer of 8 red marbles in the bag. 40/5=8, 8*1=8

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