X 1 = 3 * cos 120° = - 3 cos 60° = - 3/2 = - 1.5
y 1 = 3 * sin 120° = 3 sin 60° = 3√3 / 2 = 2.598
x 2 = 0.5 * cos 49° = 0.328
y 2 = 0.5 * sin 49° = 0.37735479
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d = [( x 2 - x 1 )² + ( y 2 - y 1 )²]^(1/2)
d = [ ( 0.328 + 1.5 )² + ( 0.37735479 - 2.598) ] ^(1/2)
d = ( 3.341584 +4.931265 )^(1/2)
Answer: The distance is :
d = 2.876256
Parallel lines have the same slopes (but different y intercepts). Parallel lines never cross. Parallel lines are the same distance from each other no matter where you are on either line. Think of it like a pair of perfectly straight railroad tracks.
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Perpendicular lines cross at one point. The two lines form a 90 degree angle. The two slopes multiply to -1, which is another way of saying that the slopes are negative reciprocals of one another. For example, a line with a slope of 2/3 and another line with a slope of -3/2 has these two values multiply to -1; therefore showing they are perpendicular lines.
Answer: t^2=-f-576/16
Step-by-step explanation:
Step 1. Switch the equation around:
-16t^2+576=f
Step 2. Subtract 576 from each side:
-16t^2+576-576=f-576
Step 3. Now simplify:
-16t^2=f-576
Step 4. Divide everything now by -16:
-16t^2/-16=f/-16-576/-16
Step 5. Simplify again:
t^2=-f-576/16
Hope I could help! :)
Answer:

Step-by-step explanation: