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3 years ago

Answer this question please.

Mathematics

1 answer:

algol [13]3 years ago

6 0

4x+3x+x=180 [ASP of a triangle]
8x=180
x=22.5
Therefore,
4x=4*22.5=90°
3x=3*22.5=67.5°
x=22.5°

m angle K=67.5°
m angle L=90°
m angle KML=22.5°
m angle LMN=180-22.5=157.5°

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Free_Kalibri [48]

Answer:

The answer to the question provided is

$\frac{9}{5}$

Step-by-step explanation:

4 0

3 years ago

The area of a rectangle has decreased by 2%.

MissTica

Answer:

The other side was decreased to approximately .89 times its original size, meaning it was reduced by approximately 11%

Step-by-step explanation:

We can start with the basic equation for the area of a rectangle:

l × w = a

And now express the changes described above as an equation, using "p" as the amount that the width is changed:

(l × 1.1) × (w × p) = a × .98

Now let's rearrange both of those equations to solve for a / l. Starting with the first and easiest:

w = a/l

now the second one:

1.1l × wp = 0.98a

wp = 0.98a / 1.1l

1.1 wp / 0.98 = a/l

Now with both of those equalling a/l, we can equate them:

1.1 wp / 0.98 = w

We can then divide both sides by w, eliminating it

1.1wp / 0.98w = w/w

1.1p / 0.98 = 1

And solve for p

1.1p = 0.98

p = 0.98 / 1.1

p ≈ 0.89

So the width is scaled by approximately 89%

We can double check that too. Let's multiply that by the scaled length and see if we get the two percent decrease:

.89 × 1.1 = 0.979

That should be 0.98, and we're close enough. That difference of 1/1000 is due to rounding the 0.98 / 1.1 to .89. The actual result of that fraction is 0.89090909... if we multiply that by 1.1, we get exactly .98.

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2 years ago

What is the volume of the rectangular prism?<br> 1/3ft

IrinaVladis [17]

We know that 1 cube equals 1/3. If you count the rectangular prism, you learn that there are 30 cubes in total that make up the rectangular prism. So what I did was 1/3 times 30. You could also divided 1 by 3, and get 0.3333333333, which is equal to 1/3 (1/3 = 0.3333333333) So, you should come out with ten. Thus your answer would be D, 10ft cubed.

Hope this helps :)

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3 years ago

Pizza Time has collected data about customer pizza topping preferences. They have calculated that P(pepperoni) = 0.7, P(olives)

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3 years ago

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago