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Paladinen [302]
3 years ago
11

Let f(x)=x^2 - 3x - 4 . What is the average of change from x=7 to x=10?

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0
You need to calculate the following expression:

   f(b) - f(a)                                          [(10)^2-3(10)-4]-[(7)^2-3(7) -4]
 --------------- , which in this case is:   ------------------------------------------
       b - a                                                              10-7



Be sure to do the calculations inside each set of square brackets separately BEFORE attempting the subtraction in  [(10)^2-3(10)-4]   -   [(7)^2-3(7) -4]

By the way:  You mean "average rate of change," not "average of change."
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If Charlie will only go to a single ride one time the possible rides he could go on would be 0 rides to all 18 rides for a domain of [0,18]. The output of the maximum and minimum x values would give us 0 dollars for riding 0 rides and 31.50 for riding all 18 (1.75 *0 = 0) and (1.75*18 = 31.50) so the range is [0, 31.50] 
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The endpoints of directed line segment PQ have coordinates of P(-7, -5) and Q(5,3). What are the coordinates of point A, on PQ,t
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Answer:

Therefore the co-ordinate of the point A is (-4,-3)

Step-by-step explanation:

If A(x₁,y₁) and B(x₂,y₂)  is divided by a point in ration m:n internally.

Then the co-ordinate of the point is  (\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_2}{m+n}).

Given two points are P(-7,-5) and Q(5,3).

A point A on PQ, that divides PQ into a ratio of 1:3.

Since the point A lies on the PQ.

Therefore it divides the line segment PQ internally.

Here x₁= -7,y₁= -5 ,  x₂= 5,y₂ =3, m=1,n=3

Therefore the co-ordinate of the point A is

(\frac{5.1+(-7).3}{1+3},\frac{3.1+(-5).3}{1+3})

=(\frac{-16}{4},\frac{-12}{4})

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