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SOVA2 [1]
2 years ago
11

Find the Square of 8^2

Mathematics
2 answers:
boyakko [2]2 years ago
8 0

Answer:

64

Step-by-step explanation:

Anit [1.1K]2 years ago
5 0

Answer:

64

Step-by-step explanation:

8^2

= 8 * 8

64

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

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-7(4-x)+4≥-18+7x<br> Solve the inequality
NikAS [45]

Answer:

0 \geqslant 6

Step-by-step explanation:

- 7(4 - x) + 4 \geqslant  - 18 + 7x \\  - 28 + 7x + 4 \geqslant  - 18 + 7x \\  - 24 + 7x \geqslant  - 18 + 7x \\ 7x - 7x \geqslant 24 - 18 \\ 0 \geqslant 6

7 0
2 years ago
Helppppp I need help I will make u a brainlist
nadezda [96]

Answer:

answer is D

Step-by-step explanation:

pretty simple

5 0
3 years ago
Barkley's team won 40% of their games last season. If they won 12 games total last season, how many games did they play?
stiv31 [10]

Answer:

D. they played 30 games in total

Step-by-step explanation:

By a process of elimination we can determine that D is the answer.

30 is the only answer that gives 12 when multiplied by 0.40

in other words, 12 is 40% of 30

4 0
3 years ago
Read 2 more answers
Combine like terms (simplify)
andre [41]
1) 8x-13
2)19r-19s
3)8m-10n
Solve in the parentheses then label the ones with the same variable and solve those setting up the equation with variable first. Do check this I am not perfect.

Hope this helped! ;)
6 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
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