The value of N/10 is 372.
The characters can be chosen from the word "AIME" or the number "2007".
There are 7 different characters that can be picked, with 0 being the only number that can be repeated twice.
There are two possible cases.
The first case is given below :
If 0 appears 0 or 1 time in the sequence, the number of possible sequences is 7!/(7-5)!.
If 0 appears 0 or 1 time in the sequence, the number of possible sequences is 2520.
The second case is given below :
If 0 appears twice in the sequence, the number of places to fill 0 is 5C2.
If 0 appears twice in the sequence, the number of places to fill 0 is 10.
The number of ways to place the remaining three characters is 6!/(6-3)!.
The number of ways to place the remaining three characters is 120.
The total number of ways in the second case is 10*120 = 1200.
The total number of ways is 2520 + 1200.
The total number of ways is 3720.
N = 3720
We have to find the value of (N/10).
N/10 = 3720/10
N/10 = 372
Learn more about sequences here:
brainly.com/question/21961097
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