Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a <span>
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3 0

3 years ago

Line 1 passes through the points -2,7 and 3,3. Line 2 passes through the points 5,1 and 9,1. Find the slope of each line. Which

RSB [31]

Answer:

The slope of the given line 1 is -4/5.

The slope of the given line 2 is 0.

The line 2 has a greater slope then line 1.

Step-by-step explanation:

The slope of a line with points (x1,y1) and (x2,y2) is given as:

$m = \frac{y_2- y_1}{x_2-x_1}$

Now, Here the, points of the line 1 are A (-2,7) and B (3,3)

So, here, the slope of line AB is $m = \frac{3 -7}{3-(-2)} = \frac{-4}{3 +2} = \frac{-4}{5}$

Hence, the slope of the given line 1 is -4/5.

Now, Here the, points of the line 2 are P (5,1) and Q (9,1)

So, here, the slope of line PQ is $m = \frac{1-1}{9-5} = \frac{0}{4} = 0$

Hence, the slope of the given line 2 is 0.

Now, as we can see 0 > ( -4 / 5)

So, the line 2 has a greater slope then line 1.

5 0

3 years ago

Need help ASAP with number 5

vredina [299]

Costs would be nine dollars for the lemons and four dollars for the sugar ($-13.00). You end up losing only fifty cents throughout, so you would have had to sell (.5×25=12.50) 25 cups to pay for all but fifty cents.

Answer is 25 cups

4 0

3 years ago

Help, WIll give 20 points

Kisachek [45]

Answer:

i dont know

Step-by-step explanation:

6 0

3 years ago