Answer:
Density of 40 mL of liquid that has a mass of 20 g = 20 / 40 = 0.5 g / cc
Answer:
10.
Explanation:
Hello,
In this case, for the given reaction:
By knowing the law of conservation of mass must be respected, the following coefficients do balance the chemical equation:
So the sum of all the coefficients is 10.
Regards.
Answer:
(a) m = 50.916 g
(b) CO2 is the limiting reagent and C is the reagent in excess.
(c) the mass excess left = 4.084 g
Explanation:
Balance the given equation first:
(a) Given:
mass of CO2 = 40.0 g
mass of C = 15.0 g
mass of CO = ?
To find the mass of CO that will be produced, we need to find the limiting reactant first. To find the limiting reactant we will calculate the number of moles of each reactant, the reactant with less number of moles is the limiting reactant.
CO2:
n = m/M where m is the mass and M is the molar mass
n = 40.0g/44.01 g/mol
n = 0.909 mol
C:
n = m/M
n = 15.0 g/12,0107 g/mol
n = 1.249 mol
CO2 is the limiting reagent and C is the reagent in excess.
Grams of CO that will be produced:
The molar ratio between CO2 and CO is 1:2
Therefore the number of moles of CO = 0.909 x 2 = 1.818 mol
m = n x M
m = 1.818 mol x 28,01 g/mol
m = 50.916 g
(c) To find how much of the reagent in excess will be left we will use the stoichiometry
n = 0.909 mol
m = 0.909 mol x 12.0107 g/mol
m = 10.916 g
15.0 g - 10.916 g = 4.084 g
Therefore the mass excess left = 4.084 g
Density is the mass of compound divided by its volume can be shown as follows:
40 mL of snow having 20 g of mass calculated from density.
Now, 10 cm of snow = 3.93 inches = 20 g
As, 10 inches of rain will produce 11 inches of ice as the volume of ice is bigger than rain water.
10 inches rain = 11 inches snow
3.93 inches of snow produced by
Thus, 3.57 incehs of rain produces by 10 cm snow.