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olga2289 [7]
3 years ago
15

The burning of the magnesium becomes uncontrolled (it burns brightly). Oops! Will the reported mole ratio of magnesium to oxygen

be too high or too low as a result of this technique error?
Chemistry
1 answer:
vfiekz [6]3 years ago
5 0

Answer

Mole ratio of magnesium to Oxygen will be too low.

Explanation:

When magnesium burns in air, it reacts with oxygen vigorously to form an ionic compound,MgO with a flame that is a brilliantly white. Normally, stability of an atom depends on whether their outermost shell contains maximum electrons. Durning combination with Oxygen, Magnesium tends to give two of its electron causing it to be stable because it has a full outermost shell. It forms Mg+2 ion, Oxygen, on the other hand gains the two electrons, which fills its outermost most shell. It also now has more electrons than protons

The MOLE RATIO of magnesium to oxygen would be too low, because there will be MORE oxygen present than there should have been.

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What is the mass of 4,48 L of SO2 at STP?
Trava [24]

Answer:

2 moles

Explanation:

Hi there !!

Given volume = 44.8 litres

Molar volume = 22.4 litres

No: of moles = Given volume / Molar volume

                    = 44.8 / 22.4 = 2 moles

3 0
3 years ago
Read 2 more answers
The density of a substance is 17.5 g/mL. Determine the volume (in mL) of 63.6 g of this substance.​
andreyandreev [35.5K]

Answer:

<h2>volume = 3.63 mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

Since we are finding the volume

Making volume the subject we have

<h3>volume =  \frac{mass}{Density}</h3>

From the question

mass = 63.6 g

Density = 17.5 g/mL

Substitute the values into the above formula and solve for the volume

That's

<h3>volume =  \frac{63.6}{17.5}</h3>

We have the final answer as

<h3>volume = 3.63 mL</h3>

Hope this helps you

5 0
3 years ago
Definition: This is the energy that comes to Earth from the Sun.
laiz [17]

Answer:

well to me it is called natural energy

7 0
2 years ago
when 6g acetic acid is dissolved in 1000cm3 of solution then how many molecules ionize out of 1000 acetic acid molecules
iVinArrow [24]

Answer:

24.8 molecules are ionized from 1000 acetic acid molecules.

Explanation:

Acetic acid, CH₃COOH dissociates in water, thus:

CH₃COOH ⇄ CH₃COO⁻ + H⁺

Ka = 6.3x10⁻⁵ = [CH₃COO⁻] [H⁺] / [CH₃COOH]

<em>That means amount of CH₃COO⁻ (the dissociated form) that are produced is followed by the equilibrium of the weak acid.</em>

<em />

The initial molar concentration of acetic acid (Molar mass: 60g/mol) is:

6g ₓ (1mol / 60g) = 0.1 moles acetic acid, in 1000cm³ = 1L.

0.1 moles / L = <em>0.1M</em>

The 0.1M of acetic acid will dissociate producing X of CH₃COO⁻ and H⁺, thus:

[CH₃COOH] = 0.1M - X

[CH₃COO⁻] = X

[H⁺] = X

Replacing in Ka formula:

6.3x10⁻⁵ = [CH₃COO⁻] [H⁺] / [CH₃COOH]

6.3x10⁻⁵ = [X] [X] / [0.1 - X]

6.3x10⁻⁶ - 6.3x10⁻⁵X = X²

6.3x10⁻⁶ - 6.3x10⁻⁵X - X² = 0

Solving for X

X = - 0.0025 → False solution, there is no negative concentrations.

X = 0.00248M

That means, a 0.1M of acetic acid produce:

[CH₃COO⁻] = X = 0.00248M solution of the ionized form.

In a basis of 1000 molecules:

1000 molecules × (0.00248M / 0.1M) = 24.8

<h3>24.8 molecules are ionized from 1000 acetic acid molecules.</h3>
8 0
3 years ago
Consider the following equation in chemical equilibrium:
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Answer:

D

Explanation:

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3 years ago
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