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vovangra [49]
2 years ago
14

Solve for X I need help please

Mathematics
1 answer:
KiRa [710]2 years ago
8 0

Answer:

Step-by-step explanation:

Angles EBC and EDC are the same. and straight lines equal 180

so now to solve for x

180=134+10x+6\\180-134=134+10x+6-134\\46=10x+6\\46-6=10x+6-6\\40=10x\\40/10=10x/10\\4=x

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Alenkasestr [34]

Answer:

○ -\frac{\sqrt{6} + \sqrt{2}}{4} = \frac{-\sqrt{6} - \sqrt{2}}{4}

Step-by-step explanation:

Input this trigonometric ratio into a scientific calculator, and you will end up with the above answer.

* I also included its high term, so you know which answer to choose from.

I am joyous to assist you anytime.

7 0
3 years ago
If 3/8 of a class is absent what percentage of the class is present
ioda

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37.5% of the class is present

6 0
2 years ago
I NEED HELP THIS IS MY LASST ONE UNTIL
Gelneren [198K]

Answer:

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3 years ago
The entire group beging studied and from which sample are taken is called the​
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5 0
3 years ago
FOR BRAINLIEST ANSWER ONLY:<br><br> 2.<br><br> 3.<br><br> 4.<br><br> 6.
nasty-shy [4]

Answer:

2. x = 2 & y = 4

3. x = 4 & y = 2

Step-by-step explanation:

2. x + y = 6

  2x + y = 8  (multiply the first equation by -1,  so you can eliminate the ys)

- x - y = -6

2x + y = 8  (now add the variables together)

x = 2 (plug in x in one of the equations to find out y)

x + y = 6

(2) + y = 6

-2           -2

y = 4

3. 3x + y = 14

          x = 2y (plug in x into the first equation and solve it for y)

3(2y) + y = 14

6y + y = 14

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y =  2  (plug in y in one of the equations to find out x)

x = 2y

x = 2(2)

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4.  One number (x) is 2 more (+2) than twice (times 2) as large as another. their sum is 17. Find the numbers.

2x + 2 = 17 (solve for x)

     -2     -2

2x = 15

x = 7.5

6. 7 (4x + 1) - (x + 6) (start by distributing 7 into the first parenthesis)

  (28x + 7) - (x + 6) (do the same to the other parenthesis by distributing -1)

  (28x + 7)  (-x - 6) (and now just combine like terms)

   28x + 7 - x - 6

   28x - x + 7 - 6

   27x + 1

i hope this helped! if you have any question, pls let me know!

6 0
3 years ago
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