1(3694820-1223400=2471420. Ans. B
2)4*40*0.05=8 Ans. B
3)Ans. D
4)2*3*2*3=6*6=36 Ans. 2,2,3,3
5)4*(10)/2=40/2=20 Ans 20
6) Ans. Distributive Property
7)Ans. 5
8)Ans. 60° angle, because 90-30=60
Answer:
20
Step-by-step explanation:
The sides of the 4-sided figure are the same length, so we can find the perimeter (sum of side lengths) by multiplying one side length by 4.
<h3>Side length</h3>
Points F(-2, -2) and G(-2, 3) lie on the same vertical line: x = -2. The distance between them is the difference of their y-coordinates:
FG = (3 -(-2)) = 5
Each side is 5 units long.
<h3>Perimeter</h3>
The length of the four sides is ...
P = 4s = 4(5) = 20
The perimeter of the rhombus is 20 units.
Answer:
P(2) = 4
Step-by-step explanation:
P(X) = -2X4 + 4X3 - X + 6
Use the remainder theorem to find quotient and remainder and the value of P(2)
First add in any missing exponents: P(x) = -2x4 + 4x3 + 0x2 -x + 6
Write all the coefficients in a line (including the constant) with the number being solved for off to the left:
Bring down the first coefficient (-2), multiply it by the term in question (2), carry the product up under
the 2nd coefficient and then add down (4-4=0), carry up the sum and repeat process across. The last
sum is the answer for P(2)
(2) -2 4 0 -1 6
-4 0 0 -2
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-2 0 0 -1 4
P(2) = 4
check the answer: P(2) = -2(24) + 4(23) -2 + 6 = -2(16) +4(8) + 4 = 4 Our answer is correct
The quotient is what we would bet by dividing the original equation by the polynomial (x-2). The
answer is given by the bottom numbers which will begin an one lower exponent than the original.
Quotient is: -2x3 + 0x2 + 0x -1 = 2x3 - 1
The remainder is: 4/(x-2)
1. Expand by distributing terms.
5x times 3 + 5x times -7y
2. Simplify 5x times 3 to 15x.
15x + 5x times -7y
3. Simplify 5x times -7y to -35xy.
15x - 35xy
Then you’re done. Hopefully this helps.
Answer:
y = - 5x + 7
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + b ( m is the slope and b the y- intercept )
Here m = - 5 and b = 7, thus
y = - 5x + 7 ← equation of line