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Elenna [48]
3 years ago
10

Which graph represents an even function?

Mathematics
2 answers:
xxMikexx [17]3 years ago
6 0

Answer:

last graph

Step-by-step explanation:

Graphs of functions that are ODD, are symmetric about the origin.

Graphs of function that are EVEN, are symmetric about y-axis.

We need to figure out which one of the 4 are EVEN. So we take y-axis as the mirror and see both sides, LEFT and RIGHT and see i the points are symmetric or not.

Graph 1, 2, 3  ----  not symmetric about y-axis

Graph 4  -------  Definitely every point to left side of y-axis has a corresponding mirror point to the right of y-axis. So this is an EVEN FUNCTION.

Gnom [1K]3 years ago
5 0

Answer:

D-the last graph on Edg2020

Step-by-step explanation:

Hope this helps!!! Have a great day!!!   : )

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Answer:

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Step-by-step explanation:

Use the equation y = mx + b.

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Step-by-step explanation:

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Answer:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

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Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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s represent the sample standard deviation

n represent the sample size  

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The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Assuming that the deviation is known we can express the margin of error is given by this formula:

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And on this case we have that ME =\pm 3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

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