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Radda [10]
3 years ago
7

Galvanized Products is considering purchasing a new computer system for their enterprise data management system. The vendor has

quoted a purchase price of $130,000. Galvanized Products is planning to borrow 1/4th of the purchase price from a bank at 12.00 % compounded annually. The loan is to be repaid using equal annual payments over a 3-year period. The computer system is expected to last 5 years and has a salvage value of $5,200 at that time. Over the 5-year period, Galvanized Products expects to pay a technician $20,000 per year to maintain the system but will save $51,000 per year through increased efficiencies. Galvanized Products uses a MARR of 20.00 %/year to evaluate investments.
What is the present worth of this investment?
Business
1 answer:
alekssr [168]3 years ago
3 0

Answer:

The present worth of this investment = -$31,204.78

Explanation:

Note: See the attached excel file for the calculation of the present worth of this investment (in bold red color).

In the attached excel file, the following are used:

Loan from bank = Purchase price * (1 / 4) = $130,000 * (1 / 4) = $32,500

Initial cost = Purchase price - Loan from bank = $130,000 - $32,500 = $97,500

The annual required equal loan payments is calculated using the formula for calculating loan amortization as follows:

P = (A * (r * (1 + r)^n)) / (((1 + r)^n) - 1) .................................... (1)

Where,

P = Annual required equal loan payment = ?

A = Loan amount from bank = $32,500

r = interest rate = 12%, or 0.12

n = number of payment years = 3

Substituting all the figures into equation (1), we have:

P = Annual required equal loan payment = ($32,500 * (0.12 * (1 + 0.12)^3)) / (((1 + 0.12)^3) - 1) = $13,531.34

From the attached excl file, the present worth of this investment is equal to -$31,204.78

Download xlsx
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ivolga24 [154]

Answer:

Journal Entry

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To record the transfer of product cost from Department F to Department G.

Explanation:

a) Data and Calculations:

Number of units assembled in Department F = 108,000

Total product cost (DM, DL, and FO) = $90,000

Additional inspection cost in Department H = $26,000

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Transfer of product cost from Department F to Department G:

Department G Work in Process $90,000

Department F Work in Process $90,000

4 0
3 years ago
This year, Major Healy paid $40,000 of interest on a mortgage on his home (he borrowed $800,000 to buy the residence in 2015; $9
icang [17]

Answer:

$50,000

Explanation:

The computation of the interest expense for deduction is shown below:

= Interest on a mortgage on his home + Interest on a mortgage on his vacation home  

= $40,000 + $10,000

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All other information which is given in the question is not relevant for the computation part. Hence, ignored it  

We simply add both types of interest related to a mortgage on the home

5 0
3 years ago
Listed as follows are nine technical accounting terms.
swat32

Answer:

a. Book value

b. Materiality

c. Matching principle

d. Unrecorded revenue

e. Adjusting entries

f. Unearned revenue

g. Prepaid expenses

h. Accumulated depreciation

Explanation:

The assets are recorded at cost and then depreciated over their useful lives . The net balance of an asset being the cost less its accumulated depreciation is its Net Book Value.

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Any revenue earned but not recorded or billed is known as unrecorded revenue.

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Advances received for services to be provided after the period end is recorded as  unearned revenue.

Amounts paid in advance for services/  benefits to be received in the future are known as prepaid expenses

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4 0
3 years ago
The following information describes the production activities of Mercer Manufacturing for the year.
Vanyuwa [196]

Answer:

Actual Quantity = 28,000

Actual Price  = 4.90

Standard Quantity = 25,800  

Standard Price  = 4.85

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= (4.85 - 4.90) * 28,000

= $1,400 U

b. Direct Material Quantity variance = (Standard Quantity – Actual Quantity)*Standard price

= (51,600*0.5 - 28,000)*4.85

= $10,670 U

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4 0
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Answer:

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4 0
4 years ago
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