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3 years ago

HELP PLZ BRAINIEST TO WHOEVER RIGHT

Mathematics

1 answer:

NISA [10]3 years ago

7 0

It’s the first one because it’s starting at 25!!!!

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Kenya kon sells dishwasher. he earns an 8% commission on sales. how much must he sell in order to earn $3000

JulsSmile [24]

Answer:

he has to sell 375

Step-by-step explanation:

just do 3000 (the whole) and 8 ( the profit) you'd get 375

3 0

3 years ago

Determine the models that could represent a compound interest account that is growing exponentially.

horrorfan [7]

Answer:A(t)= 2,675(1.003)12t

A(t)=4170(1.04)t

A(t)=5750(1.0024)2t

Step-by-step explanation:Exponential growth is also called growth percentage.

It is calculated using 100% of the original amount plus the growth rate . Example if the amount grows by 5% yearly.5%=0.05

It is written thus(1+0.005)=1.05.

It is usually written in decimal.

The formular for compound interest that is growing exponentially is written as

A=P (1 + i)^N

Looking at the 5 A(t) equations,only 3 of it are growing exponentially.

8 0

3 years ago

15. A bag contains 8 blue chips, 7 green chips, and 2 white chips. If three chips are drawn

lys-0071 [83]

8+7+2= 17 total
First blue chip chance = 8/17
Second blue chip chance = 7/16 as it’s without replacement so the total decreases by 1.
Green chip= 7/15 as again without replacement the total has been reduced by 2

3 0

3 years ago

A movie theater charges $10.00 for an adult ticket to an evening showing of a popular

Stella [2.4K]

Just go to quiz lit and it’ll give you all the answers just use safari

3 0

3 years ago

Now, lets evaluate the same integral using power series. first, find the power series for the function f(x = \frac{32}{x^2+4}. t

BlackZzzverrR [31]

No idea what the previous part of the problem is, but you have

$f(x)=\dfrac{32}{x^2+4}=\dfrac8{1-\left(-\frac{x^2}4\right)}=\displaystyle8\sum_{n\ge0}\left(-\frac{x^2}4\right)^n$
$f(x)=\displaystyle8\sum_{n\ge0}\left(-\dfrac14\right)^nx^{2n}$

which is valid for $\left|-\dfrac{x^2}4\right|$ , or $|x|$ . So the integral from 0 to 2 is

$\displaystyle\int_0^2f(x)\,\mathrm dx=\int_0^28\sum_{n\ge0}\left(-\frac14\right)^nx^{2n}\,\mathrm dx$
$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\int_0^2x^{2n}\,\mathrm dx$

Note that since the power series only converges on the interval if $x$ is strictly less than 2, which means we have to treat this as an improper integral.

$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\int_0^tx^{2n}\,\mathrm dx$ [/tex]
$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\frac{x^{2n+1}}{2n+1}\bigg|_{x=0}^{x=t}$
$=\displaystyle8\sum_{n\ge0}\frac{(-1)^n}{2^{2n}(2n+1)}\lim_{t\to2^-}t^{2n+1}$
$=\displaystyle16\sum_{n\ge0}\frac{(-1)^n}{2n+1}$
$=16-\dfrac{16}3+\dfrac{16}5-\dfrac{16}7+\dfrac{16}9+\cdots$

6 0

3 years ago