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2 years ago

Simplify -2x - 2y - 2z + 5x - 2y - 4z

Mathematics

1 answer:

jonny [76]2 years ago

4 0

Answer: 3x-4y-6z

Step-by-step explanation:

First collect the like terms and you get:
-2x + 5x - 2y - 2y - 2z - 4z
Add similar elements:
3x - 2y - 2y - 2z - 4z
And you do it again and you get: 3x-4y-2z-4z
then just take away -4z from -2z and you get: 3x-4y-6z

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What is the slope of the line shown above?

Nataly_w [17]

Answer:

1/4

Step-by-step explanation:

we can take two points on the line: (0,2) and (4,3)

to find slope:(2-3)/(0-4)

1/4

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1 year ago

Find the derivative of f(x) = 11x2 + 5x at x = 9.

Yakvenalex [24]

F(x) = 11x² + 5x

f'(x) = 22x + 5

Hence,

f'(9) = (22 * 9) + 5 = 198 + 5 = 203

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2 years ago

Read 2 more answers

What is the discriminante of 9x^2+10x

Leni [432]

The discriminant of y=ax^2+bx+c is b^2-4ac

given
9x^2+10x+0
a=9
b=10
c=0

discriminant=10^2-4(9)(0)=100-0=100

the discriminant is 100

6 0

2 years ago

25 POINTS, I DONT UNDERSTANDDDDDD :C WHAT IS SO MISLEADING ABOUT THIS GRAPH???

Kisachek [45]

Answer:

honestly, the graph look totally fine...

If one ere pressed to find something to complain about it, one could suggest that you do not know if this was the starting price of the stock or the ending price of the stock each day?... One could also argue that to be a bit more meaningful you might want to know the range of prices during each day...

look up what is called a candle stick graph.. each day looks like a candlestick... the top is the highest value each the bottom the lowest, and there is a line in the candle that shows the closing price

Step-by-step explanation:

3 0

2 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

2 years ago

Simplify -2x - 2y - 2z + 5x - 2y - 4z​

Simplify -2x - 2y - 2z + 5x - 2y - 4z