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ohaa [14]
3 years ago
15

Urgent!! Math help!!

Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

7.21

Step-by-step explanation:

14^2-12^2=52

\sqrt{52}=7.21

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Scores on an aptitude test are distributed with a mean of 220 and a standard deviation of 30. The shape of the distribution is u
Evgen [1.6K]

Answer:

P(215<X<225) = 0.7620

Step-by-step explanation:

The shape of the distribution is unknow, however, the shape of the sampling distributions of the sample mean is approximately normal due to the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 220, \sigma = 30,n = 50, s = \frac{30}{\sqrt{50}} = 4.2426

P(215<X<225)

This is the pvalue of Z when X = 225 subtracted by the pvalue of Z when X = 215. So

X = 225

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{225 - 220}{4.2426}

Z = 1.18

Z = 1.18 has a pvalue of 0.8810

X = 215

Z = \frac{X - \mu}{s}

Z = \frac{215 - 220}{4.2426}

Z = -1.18

Z = -1.18 has a pvalue of 0.1190

0.8810 - 0.1190 = 0.7620

P(215<X<225) = 0.7620

6 0
3 years ago
A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of
jenyasd209 [6]

Answer:

Ix = Iy = \frac{ρπR^{4} }{16}

Radius of gyration x = y =  \frac{R}{4}

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is \frac{MR^{2} }{2}. Moment of inertia of quarter disk about its perpendicular is \frac{MR^{2} }{8}.

Now using perpendicular axis theorem, Ix = Iy = \frac{MR^{2} }{16} = \frac{ρπR^{4} }{16}.

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0
4 years ago
HELP, WILL GIVE BRAINLIEST!!
jarptica [38.1K]

Answer:

12.3 cm and 19.3 cm

4 0
4 years ago
Equivalent polynomial to 6-(2-4x)
svetoff [14.1K]
The answer would be 4(x+1).
6 0
4 years ago
If 15.5 gallons are $24.16, how much is it for one gallon
nlexa [21]

Answer:

$1.55870968

Step-by-step explanation:

24.16dollars/15.5gallons = 1.55870968dollars/gallon

8 0
3 years ago
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