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gizmo_the_mogwai [7]
3 years ago
5

Yesterday, the price of a loaf of bread at five supermarkets was $1.54, $1.69, $1.79, $1.57, and $1.71, but today each supermark

et raised its price by $0.05. What is today's mean price of a loaf of bread at the five supermarkets?
A. $1.71 B. $1.76 C. $1.81 D. $1.66
Mathematics
1 answer:
zheka24 [161]3 years ago
5 0
The answer is definately 
1.74 
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Aloiza [94]

Answer:

Step-by-step explanation:

3/4

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What’s the area of 36 square meters perimeter of 30 meters what’s the width and length of those?
Anvisha [2.4K]
≠ means not equal to
L x w = 36
2L + 2w = 30

1. Find the multiples of 36

1 and 36
2 and 18
3 and 12
4 and 9
6 and 6

2. Figure out which set of numbers multiplied by 2 equals 30.

For 1 and 36:
2(1) + 2(36) = 2 + 72 = 74 ≠ 30

For 2 and 18:
2(2) + 2(18) = 4 + 32 = 36 <span>≠ 30

For 3 and 12:
2(3) + 2(12) =  6 + 24 = 30

So your answer is 3 and 12</span>
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A code consists of a single digit number from 0-9 and a letter from the alphabet. What is the probability that the code is 3Z? W
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Write the expression as the sine or cosine of an angle sin(pi/7) cos(x) + cos(pi/7) sin(x)
Natasha_Volkova [10]

Answer:

\sin(\frac{\pi}{7}+x)

Step-by-step explanation:

We are going to use the identity

\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)

because this identities right hand side matches your expression where

a=\frac{\pi}{7} and b=x.

So we have that \sin(\frac{\pi}{7})\cos(x)+\cos(\frac{\pi}{7})\sin(x) is equal to \sin(\frac{\pi}{7}+x).

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The number of violent crimes committed in a day possesses a distribution with a mean of 2.2 crimes per day and a standard deviat
VARVARA [1.3K]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

Step-by-step explanation:

For this case we have the following info given:

\mu = 2.2 represent the mean

\sigma = 6 represent the deviation

We select a sample size of n=100. This sample is >30 so then we can use the central limit theorem. And we want to find the distribution for the sample mean and we know that the distribution is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

6 0
3 years ago
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