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Soloha48 [4]
3 years ago
6

Find f(-3): f(x) =X^2 +4x F( )= F( )= F( )= F( )=

Mathematics
1 answer:
bazaltina [42]3 years ago
4 0

Step-by-step explanation:

f(_3)=(_3)^2+4(_3)

=_3

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5/6-1/3= (reduced form please)
Masteriza [31]
The correct answer is 0.5 as a decimal as a fraction it is 5/10 = 1/2 so it is what ever one u need 1/2 or 5/10 or 0.5. Hope this helps! ;D
7 0
3 years ago
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What is the recursive rule for the following sequence: -9, -2, 5, 12, ….
tino4ka555 [31]

Answer:

The answer is option (C)=an-1+7

Step-by-step explanation:

A recursive rule is a formula that in which each term is expressed as a function of its preceding term(s), meaning in order to get to the nth term you have to express it in a form of the term that comes before it. In our case the a(n-1) term

So for the sequence -9, -2, 5, 12

The nth term is any number on the sequence and

  • -2 is the a(n-1) term for -9
  • 5 is the a(n-1) term for -2
  • 12 is the a(n-1) term for 5

So we need to find out what we have to do to the preceding term to get the next.

To get -2 from -9 we have to add 7 to -9; -9+7=-2

To get 5 from -2 we have to add 7 to -2; -2+7=5

To get 12 from 5 we add 7 to 5; 7+5=12

So the recursive rule would be= a n-1+7

5 0
3 years ago
Can someone help me finger out my homework please
topjm [15]

Answer:

(1) w = 6.4

(2) w = -67

(3) q = 336

(4) z = -14

(5) x = 9

(6) y = 3

(7) x = 8

(8) x = -16

(9) x = 54

(10) x = 13.5

Step-by-step explanation:

Ik u need it quick so mb for not explaining. Good luck

4 0
3 years ago
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This high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards wide
goldfiish [28.3K]

Answer:

Step-by-step explanation:

1. 1923.25

2.about 3846.5 yards

3.219.91

4.639.82

7 0
3 years ago
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Find the value of the derivative (if it exists) at the indicated extremum. (If an answer does not exist, enter DNE.)
Liono4ka [1.6K]

Answer:

The answer is "0".

Step-by-step explanation:

Please find the correct question in the attached file.

Given value:

\to f(x) =\frac{x^2}{x^2+5}\\\\

Formula:

\bold{\frac{d}{dx} \frac{u}{v} = \frac{ v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}}

\to f'(x) =\frac{(x^2+5) 2x -2x^3 (2x)}{(x^2+5)^2}\\\\\to f'(0) =\frac{(0^2+5)2(0) -4(0)^4}{(0^2+5)^2}\\\\\to f'(0) =\frac{(0)(5) -2(0)}{(5)^2}\\\\\to f'(0) =\frac{0 - 0}{(5)^2}\\\\\to f'(0) =\frac{0}{25}\\\\\to f'(0) = 0

6 0
3 years ago
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