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bonufazy [111]
3 years ago
12

You are fencing a rectangular puppy kennel with 25 ft of fence. The side of the kennel against your house does not need a fence.

This side is 9 ft long. Find the dimensions of the kennel.
Mathematics
1 answer:
Sever21 [200]3 years ago
5 0

Answer:

9 by 8 ft

Step-by-step explanation:

if you subtract the 9 ft for the side opposite your house you are left with 16. divide 16 by 2 for the sides sticking out from your house. the answer is 8 so the cage would be 9ft by 8ft

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Answer:

(6-2x)(3-2x)x=40

Step-by-step explanation:

(-2x-2x) (6+3)x=40

8x=40

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x=5

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How many combinations of 4 can you make of 25 basketball cards?
pochemuha

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Step-by-step explanation:


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Complete the following equation: a2 = b2 + c2 - ______.
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Answer:

2 bc cos A

Step-by-step explanation:

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3 years ago
The owner of a grocery store finds she can sell about 982 gallons of milk in a week if she prices it at $2.99 per gallon. If she
julia-pushkina [17]

Answer:

  • g = -1110p +4300.9
  • 804 gallons

Step-by-step explanation:

a) Price is the independent variable, so the data we are given can be written as ...

  (price, gallons) = (2.99, 982) and (2.79, 1204)

Using the 2-point form of the equation for a line, we have ...

  g = (g2 -g1)/(p2 -p1)(p -p1) +g1

  g = (1204 -982)/(2.79 -2.99)(p -2.99) +982

  g = -1110(p -2.99) +982 = -1110p +4300.9

  g = -1110p +4300.9

__

b) When p = 3.15, the predicted sales volume is ...

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Weekly sales are predicted to be 804 gallons at a price of $3.15.

6 0
3 years ago
A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo
defon

Answer:

a) The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

b) P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

c) P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

X \sim Unif (a= 10, b =12)

Part a

The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

Part b

For this case we want this probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

Part c

For this case we want this probability:

P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

3 0
3 years ago
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