Answer:
x =
Step-by-step explanation:
Given
+
= 1
Multiply through by ab to clear the fractions
bx + ax = ab ← factor out x from each term on the left side
x(b + a) = ab ← divide both sides by (b + a)
x =
Convert 40 mm to 0.5 l
1 answer:
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F = 1.8C + 32
С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒ (-10, 14)
С = 0 ⇒ F = 1.8·(0) + 32 = 32 ⇒ (0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒ (10, 50)
С = 20 ⇒ F = 1.8·(20) + 32 = 68 ⇒ (20, 68)
С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒ (-10, 14)
С = 0 ⇒ F = 1.8·(0) + 32 = 32 ⇒ (0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒ (10, 50)
С = 20 ⇒ F = 1.8·(20) + 32 = 68 ⇒ (20, 68)
You can use my photo as reference but its going to be 15/100 of 480
Answer:
SA = 1244.64 square centimeters
Step-by-step explanation:
From the attached figure
The formula of the surface area of the prism is SA = 2B + PH, where
- B is the area of its base
- P is the perimeter of its base
- H is the distance between its bases
The base of the prism is a regular hexagon with side 8 cm
If you join each vertex of the hexagon with its center you will form 6 congruent triangles with base 8 cm and height 6.93 cm
The area of the hexagon = 6 × area of a triangle
∵ The base of the triangle = 8 cm
∵ Its height = 6.93 cm
- The formula of the area of a triangle is A = × base × height
∴ Area of the triangle = × 8 × 6.93 = 27.72 cm²
- Lets find the area of the hexagon
∴ The area of the hexagon = 6 × 27 .72 = 166.32 cm²
∴ B = 166.32 cm²
The formula of the perimeter of the regular hexagon is P = 6 × s, where s is the length of its side
∵ The side of the hexagon is 8 cm
∴ P = 6 × 8
∴ P = 48 cm
∵ The distance between the two bases is 19 cm
∴ H = 19 cm
Substitute the values of B, P and H in the formula of the surface area above
∵ SA = 2(166.32) + (48)(19)
∴ SA = 332.64 + 912
∴ SA = 1244.64 square centimeters
Answer:
The coordinates of the image of point A (2, -7) are A'(-1,-2).
Step-by-step explanation:
Note: The sign is missing between y and 5 in the rule of transitional.
Consider the rule of translation is
We need to find the image of point A (2, -7).
Substitute x=2 and y=-7 in the above rule.
Therefore, the coordinates of the image of point A (2, -7) are A'(-1,-2).