All categories

3 years ago

Help Pls!!! Will give brainliest

Mathematics

1 answer:

STALIN [3.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

1 and three fourths divided by 3

Lady_Fox [76]

Answer: 3 7/12 (three and seven twelfths

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is another way to write this number? 300 + 70 + 5 + 8 300 + 70 + 10 100

ololo11 [35]

Answer:

Combine the terms

300 + 70 = 370

5/10 + 8/100

Note that first, you must find common denominators. What you multiply to the denominator, you multiply to the numerator. Multiply 10 to the numerator and denominator of 5/10

(5/10)(10/10) = 50/100

50/100 + 8/100

Combine the terms

50/100 + 8/100 = 58/100

370 58/100 is another way to write it

5 0

3 years ago

Read 2 more answers

Tristan wants to buy 12 cupcakes. Each cupcake costs $2.40. What is the best estimate for how much money Tristan should bring wi

Alenkasestr [34]

Answer: $28.80

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the slope of the line through each pair of points. (11, 1) (-7, 18)

Sonbull [250]

$\bf (\stackrel{x_1}{11}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{-7}~,~\stackrel{y_2}{18}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{18-1}{-7-11}\implies \cfrac{17}{-18}$

3 0

3 years ago

Read 2 more answers

a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

nlexa [21]

Answer:

The standard equation of the parabola is:

$y=-\frac{3}{2}x^2+12x-18$

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

$y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2$

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

$y-6=a\,(x-4)^2\\0-6=a\,(2-4)^2\\-6=a\,4\\a=-\frac{6}{4} =-\frac{3}{2}$

Then the equation of the parabola becomes:

$y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18$

7 0

4 years ago