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3 years ago

Find the distance between the following points (-2,4) (3,2)

Mathematics

1 answer:

galina1969 [7]3 years ago

8 0

Answer:

https://www.mathwarehouse.com/calculators/distance-formula-calculator.php?x1=-2&y1=.4&x2=3&y2=2

Step-by-step explanation:

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Will name brainliest

LenaWriter [7]

Step-by-step explanation:

ii) reflexive property

iii) AAS

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2 years ago

Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx

Soloha48 [4]

Answer:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

Step-by-step explanation:

For this case we need to find the following integral:

$\int x(8-x)^{3/2}dx$

And for this case we can use the substitution $u = 8-x$ from here we see that $du = -dx$ , and if we solve for x we got $x = 8-u$ , so then we can rewrite the integral like this:

$\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)$

And if we distribute the exponents we have this:

$\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du$

Now we can do the integrals one by one:

$\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C$

And reordering the terms we have"

$\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C$

And rewriting in terms of x we got:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

And that would be our final answer.

8 0

3 years ago

Qué número entero está entre -2 y 5

cestrela7 [59]

Answer:

1.5

Step-by-step explanation:

-2,-1,0,1,2,3,4,5

Le quitamos un número hasta llegar al medio. En el medio hay dos números, el 1 y el 2. Pues tenemos que buscar el promedio de los dos (1+2=3 y 3÷2=1.5).

4 0

3 years ago

What's 100 * 100? And what's the square root of that number?

dmitriy555 [2]

Answer: 100

Step-by-step explanation:

100*100= 10000

The square root of 10000 is 100.

* Hopefully this helps!

3 0

3 years ago

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