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mote1985 [20]
3 years ago
9

F(x) = 2x^2 - 4x - 5 vertex? (x,y) number of solutions? range?

Mathematics
1 answer:
lapo4ka [179]3 years ago
4 0

Answer:

F(x) = 2x^2 - 4x - 5

vertex? (1,-7)

range?

{y|y>=-7}

number of solutions?

Sorry I couldn’t find the answer, I hope this will do.

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(-2,3) is one vertex of a square on a coordinate plane. Name three points that could be the other vertices.
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4 0
4 years ago
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Answer:

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