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Novosadov [1.4K]
3 years ago
6

NO LINKS!! Please help me with these notes. Part 1a​

Mathematics
1 answer:
erik [133]3 years ago
5 0

Answers:

When we evaluate a logarithm, we are finding the exponent, or <u>    power   </u>  x, that the  <u>   base   </u> b, needs to be raised so that it equals the <u>  argument   </u> m. The power is also known as the exponent.

5^2 = 25 \to \log_5(25) = 2

The value of b must be <u>   positive    </u> and not equal to <u>   1   </u>

The value of m must be <u>   positive   </u>

If 0 < m < 1, then x < 0

A <u>   logarithmic  </u>    <u>   equation  </u> is an equation with a variable that includes one or more logarithms.

===============================================

Explanation:

Logarithms, or log for short, basically undo what exponents do.

When going from 5^2 = 25 to \log_5(25) = 2, we have isolated the exponent.

More generally, we have b^x = m turn into \log_b(m) = x

When using the change of base formula, notice how

\log_b(m) = \frac{\log(m)}{\log(b)}

If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why b \ne 1

We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.

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