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rusak2 [61]
3 years ago
6

A 10-foot by 12-foot wall has two windows that measure 3 feet by 5 feet each.

Mathematics
1 answer:
musickatia [10]3 years ago
6 0

12 ft maybe? i dunno im sorry if this is wrong

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1) Expand and simplify the following:<br>a)3(x squared plus 3x cubed - 2)​
Musya8 [376]

Answer:

3x³ + x² - 2

Step-by-step explanation:

a) 3(x squared plus 3x cubed - 2)​

x squared = x²

3x cubed = 3x³

3(x squared plus 3x cubed - 2)​

= 3(x² + 3x³ - 2)

= 3x² + 9x³ - 6

Rearrange according to power

= 9x³ + 3x² - 6

When the expression is divided by 3, it is equivalent to

3x³ + x² - 2

5 0
3 years ago
Now do you guys understand the question?? I need help.
Kipish [7]

Answer:

6th period.

Step-by-step explanation:

3 0
2 years ago
The graph of y=x^3 is transformed as shown in the graph below. Which equation represents the transformed function?
omeli [17]

Answer:

y = (-x)^3 - 4

Step-by-step explanation:

Ok, for the function:

y = x^3

When x = 0, we have:

y = 0^3  = 0

So the original graph passes through the point (0, 0)

If we look at the given graph, we can see that the y-intercept (the value of y when x = 0) is:

y = -4

So, this is the graph of y = x^3 moved down 4 units.

You can also see that the graph goes downward as x increases (and up as x decreases) while for the function:

y = x^3

as x increases, we should see that y also increases.

Then we have a reflection across the x-axis.

Ok, now let's describe a vertical shift.

For a general function f(x), a vertical shift of N units is written as:

g(x) = f(x) + N

if N is positive, the shift is upwards

if N is negative, the shift is downwards.

And for a function f(x), a reflection across the x-axis is written as:

g(x) = - f(x)

Here we first apply the reflection across the x-axis, so we get:

g(x) = -f(x)

now we apply the shift 4 units downwards

g(x) = - f(x) - 4

replacing f(x) by our function, x^3

we get:

g(x) = -x^3 - 4

And because of the odd power, we can write:

-x^3 = (-x)^3

Then the function is:

g(x) = (-x)^3 - 4

The correct option is the last one.

y = (-x)^3 - 4

3 0
3 years ago
find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (i
tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
  • L = length of incline = 100 ft and
  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

Learn more about work done here:

brainly.com/question/25970931

#SPJ1

3 0
1 year ago
Can someone solve this?
noname [10]

Answer:

\frac{5}{6}, \frac{5}{6}, and "Yes"

Step-by-step explanation:

   We will do as the instructions say.

-> See attached.

5 0
1 year ago
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