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frez [133]
3 years ago
7

Bluefin tuna are large fish that can weigh 1,500 pounds and swim at speeds of 55 miles per hour. because they are used in sushi,

a prime fish can be worth over $30,000. as a result, the western atlantic bluefin tuna have been exploited, and their numbers have declined exponentially. their numbers in thousands from 1974 to 1991 can be modeled by f (x) = 230(0.881)x, where x is the year and x = 0 corresponds to 1974. in what year were there or will there be 50 thousand tuna?
Mathematics
1 answer:
shtirl [24]3 years ago
3 0

Given exponential function

f(x)= 230 (0.881)^x

Where x is the number of years

f(x) is the number of tuna in thousands

To find out when number of tuna is 50 thousand , we plug in 50 for f(x) and solve for x

50 = 230(0.881)^x

Divide by 230 on both sides

\frac{5}{23}  = (0.881)^x

Take ln on both sides

ln(\frac{5}{23})  = ln(0.881)^x

ln(\frac{5}{23}) = x ln(0.881)

Divide by ln(0.881) on both sides

x = \frac{ln(\frac{5}{23})}{ln(0.881)}

x= 12.04

Year = 1974 + 12.04 = 1986

so in 1986 there will be 50 thousand tuna.

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\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}    

 

 

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