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zmey [24]
3 years ago
7

If you put $0.25 into a parking meter, you are paying for the right to keep your car parked for 15 minutes. You can pay more int

o the meter in order to buy more time. In this example, the INPUT or INDEPENDENT VARIABLE is:
Money

Time
Mathematics
2 answers:
Eva8 [605]3 years ago
7 0

Answer:

i think it would be time but dont quote me on that tho lol

Step-by-step explanation:

plz correct me if im wrong

Maksim231197 [3]3 years ago
5 0

Answer:

i think it would be time but dont quote me on that

Step-by-step explanation:

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Cordial is mixed with water in the ratio of 1 : 4. How much cordial is needed to make a mixture of 2 L?
Kitty [74]

Answer: If the ratio of 1:4 Cordial and water mixture is a total of 1 L, then you need a ration of 2:8 Cordial mixture two make 2 Liters mixture.

Explanation: In every 1 Cordial mixture, there is added 4 mixtures of water. (I suppose the 1:4 ratio is 1 L together). To make two Liters, we need twice as many proportions. That would mean we will need a ratio of 2:8 of cordial and water.

If I misunderstood the problem, please explain the 1:4 ratio. I need to know how many Liters is the 1:4 ratio. Is it 1/4 of a liter? 1:4 adding up to 1 Liter?

If we don't know how much Liters are in that ratio, we can't find how much Liters of mixture we need to add of both Cordial and Water to make a mixture of 2 Liters.

3 0
3 years ago
What is 7.47 divided by 3
hram777 [196]
7.47 divided by 3=2.49
3 0
3 years ago
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One month salma rented 3 movies and 2 video games for a total of $19 . the next month she rented 5 movies and 6 video games for
Doss [256]

6$ and 8$ boiiiiiiiiiiiiii


7 0
4 years ago
3/5(x-4)-1/3(2x-9)=1/4(x-1)-2​
fenix001 [56]

Answer:

Just take L. C. M it's really simple

5 0
3 years ago
Please help!!!! Will mark brainliest!! 18 points.
andreyandreev [35.5K]

Method 1:

You can use the formula of an area of equilateral triangle:

A=\dfrac{a^2\sqrt3}{4}

a - length of side

We have a = 10 yd. Substitute:

A=\dfrac{10^2\sqrt3}{4}=\dfrac{100\sqrt3}{4}=25\sqrt3\ yd^2\\\\\sqrt3\approx1.7\\\\A=25(1.7)=\boxed{42.5\ yd^2}


Method 2:

Use the Pythagorean theorem (look at he picture).

5^2+h^2=10^2

25+h^2=100           <em>subtract 25 from both sides</em>

h^2=75\to h=\sqrt{75}\\\\h=\sqrt{25\cdot3}\\\\h=\sqrt{25}\cdot\sqrt3\\\\h=5\sqrt3\ yd

The formula of an area of a trinagle:

A=\dfrac{1}{2}bh

b - base

h - height

We have b = 10 yd and h = 5√3 yd. Substitute:

A=\dfrac{1}{2}(10)(5\sqrt3)=(5)(5\sqrt3)=25\sqrt3\ yd\\\\\sqrt3\approx1.7\\\\A=25(1.7)=\boxed{42.5\ yd^2}

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3 years ago
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