You draw perpendicular bisectors to find the center of a circle circumscribed about a triangle. Hook me up with 5 stars :)
Answer:
c) ![2x + 3y = 4](https://tex.z-dn.net/?f=2x%20%2B%203y%20%3D%204)
Step-by-step explanation:
−2 = −⅔[5] + b
−3⅓
1⅓ = b
y = −⅔x + 1⅓
Then convert to Standard Form:
y = −⅔x + 1⅓
+⅔x + ⅔x
__________
⅔x + y = 1⅓ [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
3[⅔x + y = 1⅓]
![2x + 3y = 4](https://tex.z-dn.net/?f=2x%20%2B%203y%20%3D%204)
* 1⅓ = 4⁄3
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Step-by-step explanation:
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Step-by-step explanation:
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