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Eduardwww [97]
2 years ago
12

Convert the units of weight.

Mathematics
2 answers:
noname [10]2 years ago
8 0
There are 16 ounces in a pound. You only have twelve extra ounces ontop of 32 pounds so it would be a decimal since 12 ounces does not equal a pound. So, now you have to choose between A and B. To figure this out, you would just divide 12 by 16, since 16 ounces is a pound. This gets you 0.75 (3/4) of a pound. Now add the 32 pounds. 
Your answer would be B. 32.75 lb
Hope this helps and sorry if it didn't make too much sense I'm not too good at explaining things, but I tried my best. Message me if you have any questions!! Have a great day :)
elena-14-01-66 [18.8K]2 years ago
8 0
B would be your answer for this question
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sebuah kantong berisi 20 kelereng merah dan 15 kelereng putih.toni memiliki 3 kantong yang berisi kelereng dengan jumlah yang sa
oee [108]

Answer:

60

Step-by-step explanation:

The computation of the rest of the marbles is given below:

Since there is 20 red and 15 white marbles

Also the 3 bags contains same marbles

So if he gives 45 marbles, so the remaining would be

= (20 + 15) × 3 - 45

= 35 × 3 - 45

= 105 - 45

= 60

5 0
3 years ago
A rainwater collection tank is shaped like a cylinder with a diameter of 4 ft and height of 6 ft what is its volue
lana [24]
Volume = π×22<span>×6 = </span><span>75.398223686155 feet^3</span>
6 0
3 years ago
16) (1 Point) : Solve the equation
Marat540 [252]

Answer:

(B)

4 +/- 3 sqrt(2) or 4+3sqrt(2) and 4-3sqrt(2)

Step-by-step explanation:

4(c-4)^2=72

4(c-4)(c-4)=72

foil the parenthesis (first, outside, inside, last)

4(c^2 -4c -4c +16)=72

4(c^2-8c+16)=72

divide each side by 4

c^2-8c+16=18

subtract 18 from both sides

c^2-8c-2

use quadratic formula

((-b +/- sqrt((-b^2)-4ac)))/2a

((-(-8)+/-sqrt((-8)^2-4(1)(-2)))/2(1))

(8+/-sqrt(64-(-8)))/2

(8+/-sqrt(64+8))/2

(8+/-sqrt(72))/2

(8+/-sqrt(36 * 2))/2

(8+/-6sqrt(2))/2

4+/-3sqrt(2)

or 4+3sqrt(2) and 4-3sqrt(2)

3 0
2 years ago
Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red
Neporo4naja [7]

Answer:

Multiple answers

Step-by-step explanation:

The original urns have:

  1. Urn 1 = 2 red + 4 white = 6 chips
  2. Urn 2 = 3 red + 1 white = 4 chips

We take one chip from the first urn, so we have:

The probability of take a red one is : \frac{1}{3} (2 red from 6 chips(2/6=1/2))

For a white one is: \frac{2}{3}(4 white from 6 chips(4/6=(2/3))

Then we put this chip into the second urn:

We have two possible cases:

  • First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
  • Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips

If we select a chip from the urn two:

  • In the first case the probability of taking a white one is of:  \frac{2}{5} = 40%  ( 2 whites of 5 chips)
  • In the second case the probability of taking a white one is of:  \frac{1}{5} = 20%  ( 1 whites of 5 chips)

This problem is a dependent event because the final result depends of the first chip we got from the urn 1.

For the fist case we multiply :

\frac{4}{6} x \frac{2}{5} = \frac{4}{15} = 26.66%   ( \frac{4}{6} the probability of taking a white chip from the urn 1, \frac{2}{5}  the probability of taking a white chip from urn two)

For the second case we multiply:

\frac{1}{3} x \frac{1}{5} = \frac{1}{30} = .06%   ( \frac{1}{3} the probability of taking a red chip from the urn 1, \frac{1}{5}   the probability of taking a white chip from the urn two)

8 0
3 years ago
The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown
Brums [2.3K]

Answer:

The first student is correct

Step-by-step explanation:

With the given information there is already 4 inches on the rectangle. 13 x2 = 26. 26+4=30. For student two if the unknown number was 10 it would not work because the longest side is 3 less then the unknown number. 10-3=7. 7x2=14. 14+4= 28<30

8 0
3 years ago
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