<span>M can have a coordinate of (-9) or (1)
There are potentially 3 different places for point M to go. It can be placed to the left of point A, between points A and B, and to the right of point B. Let's check those three possibilities.
1. Left of point A. This works if the distance between M and A is the same as the distance between A and B. So
distance between A and B = 6 - (-1.5) = 6 + 1.5 = 7.5
So the location for M would be
-1.5 - 7.5 = -9
So point M can have the value of -9.
2. Between A and B.
This would also work. Since we want a 1:2 ratio, place M one third of the way from A to B. Since we already know the distance between A and B to be 7.5, that means that we should add 7.5/3 = 2.5 to the value of A. So
-1.5 + 2.5 = 1
So point M can also have the value of 1.
3. To the right of point B
This won't work. Point B will always be closer to M than point A will be. So it's impossible to get a ratio of 1:2.</span>
Answer:
Y=2x+0.5
Step-by-step explanation:
The gradient is 2/1=2x
The y-intercept looks to be around 0.5
Answer:
x = 1
, y = 3 thus: A is your Anser
Step-by-step explanation:
Solve the following system:
{2 x + y = 5 | (equation 1)
x + y = 4 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x + y = 5 | (equation 1)
0 x+y/2 = 3/2 | (equation 2)
Multiply equation 2 by 2:
{2 x + y = 5 | (equation 1)
0 x+y = 3 | (equation 2)
Subtract equation 2 from equation 1:
{2 x+0 y = 2 | (equation 1)
0 x+y = 3 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 1 | (equation 1)
0 x+y = 3 | (equation 2)
Collect results:
Answer: {x = 1
, y = 3
Answer:
4.5
Explanation:
I’ve attached my work below
Hope it helps, Let me know if you have any questions !
L=3$-x×2 x=D hope this helps?
