Ask question

Ask question

All categories

2 years ago

6

Tom keeps all his favorite marbels in a special leather bag right now five red marbels four blue marbels and there yellow marble

s are in the bag ,if he randomly chooses one marble to give a friend what is the probability that it is blue

1 answer:

Nezavi [6.7K]2 years ago

6 0

4/12 or 1/3? I think.

You might be interested in

What is the slope intercept of -4 and y-intercept -1

Brut [27]

Answer:

Points are given corresponding to (-8,0) and (0,-11), and you want line's equation in the form y=mx+b. Understand, you already have b=-11. If you too understand ...

Step-by-step explanation:

6 0

3 years ago

Statements about regression

galben [10]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

It is true because the square of the standard error of its estimate was its total square error divided only by the degree of freedom.
It is true because Its coefficient with Standardized Regression, beta, will have the same value as r, the approximate similarity.
It is false because Its slope b, of its equation of regression, will have the same value as r, the projected correlation.

3 0

3 years ago

15. Ellen records the time it takes for her to commute to work on 100 consecutive mornings and finds that the times are approxim

Anettt [7]

First one A second one C third one d 4th one E

4 0

2 years ago

Which statement is true about the graphs of the two lines y=-8x-5/4 and y= 1/8 x + 4/5?

PIT_PIT [208]

These two lines intersect.

6 0

3 years ago

A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f

Vitek1552 [10]

Answer:

$P(X\cap Y\cap Z)=0.05$

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert $P(X)=0.28$

Percentage of audience in second concert $P(Y)=0.42$

Percentage of audience in third concert $P(Z)=0.30$

Audience Percentage at at-least one concert $P(X \cup Y \cup Z)=0.80$

Percentage of audience at first & second concert $P(X \cap Y)=0.10$

Percentage of audience in first & third concert $P(X \cap Z)=0.08$

Percentage of audience in second & third concert $P(Y\cap Z)=0.07$

Generally the equation for probability of attending all concerts $P(X\cap Y\cap Z)$ is mathematically given by

$P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)$

$P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)$

$P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70$

$P(X\cap Y\cap Z)=0.05$

Therefore the probability that a randomly selected audient attended all the concerts

$P(X\cap Y\cap Z)=0.05$

8 0

3 years ago