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xxTIMURxx [149]

3 years ago

11

Help me ASPA PLEASE help

1 answer:

Olegator [25]3 years ago

4 0

Answer:

85

Step-by-step explanation:

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Illusion [34]

Answer:−93 3−153−53

Step-by-step explanation:

wrong answer but the answer is on google

6 0

3 years ago

2x - 5y=-15<br> can someone walk me through this?

HACTEHA [7]

The equation given in the question has two unknown variables in the form of "x" and "y". The exact value of "x" and "y" cannot be determined as two equations are needed to get to the exact values of "x" and "y". This equation can definitely be used to show the way for determining the values of "x" in terms of "y"and the value of "y" in terms of "x". Now let us check the equation given.
2x - 5y = - 15
2x = 5y - 15
2x = 5(y - 3)
x = [5(y - 3)]/2
Similarly the way the value of y can be determined in terms of "x" can also be shown.
2x - 5y = - 15
-5y = - 2x - 15
-5y = -(2x + 15)
5y = 2x + 15
y = (2x +15)/5
= (2x/5) + (15/5)
= (2x/5) + 3
So the final value of x is [5(y -3)]/2 and the value of y is (2x/5) + 3.

3 0

3 years ago

Pls help pls helppp i will giving breanlist

GaryK [48]

Answer:

[-5, 4) ∪ (4, ∞)

Step-by-step explanation:

Given functions:

$f(x)=\dfrac{1}{x-3}$

$g(x)=\sqrt{x+5}$

Composite function:

$\begin{aligned}(f\:o\:g)(x)&=f[g(x)]\\ & =\dfrac{1}{\sqrt{x+5}-3} \end{aligned}$

Domain: input values (x-values)

For $(f\:o\:g)(x)$ to be defined:

$x+5\geq 0 \implies x\geq -5$

$\sqrt{x+5}\neq 3 \implies x\neq 4$

Therefore, $-5\leq x < 4$ and $x > 4$

⇒ [-5, 4) ∪ (4, ∞)

3 0

2 years ago

If f(x) = 2x2 + 1 and g(x) = x2 – 7, find (f – g)(x).

nadya68 [22]

Answer: The required value is

$(f-g)(x)=x^2+8.$

Step-by-step explanation: The given functions are:

$f(x)=2x^2+1,\\\\g(x)=x^2-7.$

We are given to find the value of $(f-g)(x).$

We know that, if s(x) and t(x) are any two functions of a variable x, then we have

$(s-t)(x)=s(x)-t(x).$

Therefore, we have

$(f-g)(x)\\\\=f(x)-g(x)\\\\=(2x^2+1)-(x^2-7)\\\\=2x^2+1-x^2+7\\\\=x^2+8.$

Thus, the required value is

$(f-g)(x)=x^2+8.$

5 0

3 years ago

Find the slope of the line going through the points (0, -5) and (-2,1)

kvasek [131]

Answer:

$\displaystyle m=-3$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Coordinates (x, y)
Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

<u>Step 1: Define</u>

Point (0, -5)

Point (-2, 1)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

Substitute in points [Slope Formula]: $\displaystyle m=\frac{-5-1}{0--2}$
[Fraction - Denominator] Simplify: $\displaystyle m=\frac{-5-1}{0+2}$
[Fraction - Numerator] Subtract: $\displaystyle m=\frac{-6}{0+2}$
[Fraction - Denominator] Add: $\displaystyle m=\frac{-6}{2}$
[Fraction] Divide: $\displaystyle m=-3$

8 0

2 years ago