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Otrada [13]
3 years ago
7

-0.9+28 ---- 6 help me solve the task im a little lazy ​

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer:

around 4.52.

Fraction form: 4\frac{52}{100}

Step-by-step explanation:

Brainliest?

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Question 11 options:
9966 [12]

Answer:

x = 12

length = 4 cm

width = 20 cm

Step-by-step explanation:

a = lw

Plug in the givens

80 = (x - 8)(x + 8)

Multiply

80 = x^2 - 64

Add 64 to both sides

144 = x^2

Take the square root of both sides

x = ±12

(The negative root is extraneous since the dimensions can not be negative)

x = 12

length = x - 8 = 4 cm

width = x + 8 = 20 cm

7 0
2 years ago
Miller has a painting that is 4 ft by 8 ft. What will the dimensions of the painting be if he scales it down by a factor of one-
hram777 [196]
1 ft by 2 ft I believe
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3 years ago
What is the value of f in f/12.7= 15.26
Elena L [17]
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8 0
3 years ago
Read 2 more answers
Oliver read for 450 minutes this month. His goal to read for 10% more minutes next month. If Oliver meets his goal, how many min
sesenic [268]

Answer: 945

Step-by-step explanation:

this month = 450.

next month 450x10/100=45, 450+45= 495

450+495= 945

4 0
3 years ago
How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
sattari [20]
<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

  cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

  (1 -sin^2(θ))cot^2(θ) =  . . . . . replace cos^2 with 1-sin^2

  cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

  cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0
3 years ago
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